How do you detect Credit card type based on number

Question

I'm trying to figure out how to detect the type of credit card based purely on its number. Does anyone know of a definitive, reliable way to find this?

Answer 1

The first numbers of the credit card can be used to approximate the vendor:

• Visa: 49,44 or 47
• Visa electron: 42, 45, 48, 49
• MasterCard: 51
• Amex:34
• Diners: 30, 36, 38
• JCB: 35

Answer 2

Stripe has provided this fantastic javascript library for card scheme detection. Let me add few code snippets and show you how to use it.

Firstly Include it to your web page as

<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/jquery.payment/1.2.3/jquery.payment.js " ></script>

Secondly use the function cardType for detecting the card scheme.

$(document).ready(function() {              
            var type = $.payment.cardType("4242 4242 4242 4242"); //test card number
            console.log(type);                                   
}); 

Here are the reference links for more examples and demos.

1. Stripe blog for jquery.payment.js
2. Github repository

Answer 3

I use https://github.com/bendrucker/creditcards-types/ to detect the credit card type from number. One issue I ran into is discover test number 6011 1111 1111 1117

from https://www.cybersource.com/developers/other_resources/quick_references/test_cc_numbers/ we can see it is a discover number because it starts by 6011. But the result I get from the creditcards-types is "Maestro". I opened the issue to the author. He replied me very soon and provide this pdf doc https://www.discovernetwork.com/downloads/IPP_VAR_Compliance.pdf From the doc we can see clearly that 6011 1111 1111 1117 does not fall into the range of discover credit card.

Answer 4

follow Luhn’s algorithm

 private  boolean validateCreditCardNumber(String str) {

        int[] ints = new int[str.length()];
        for (int i = 0; i < str.length(); i++) {
            ints[i] = Integer.parseInt(str.substring(i, i + 1));
        }
        for (int i = ints.length - 2; i >= 0; i = i - 2) {
            int j = ints[i];
            j = j * 2;
            if (j > 9) {
                j = j % 10 + 1;
            }
            ints[i] = j;
        }
        int sum = 0;
        for (int i = 0; i < ints.length; i++) {
            sum += ints[i];
        }
        if (sum % 10 == 0) {
           return true;
        } else {
            return false;
        }


    }

then call this method

Edittext mCreditCardNumberEt;

 mCreditCardNumberEt.addTextChangedListener(new TextWatcher() {
            @Override
            public void beforeTextChanged(CharSequence s, int start, int count, int after) {

            }

            @Override
            public void onTextChanged(CharSequence s, int start, int before, int count) {

             int cardcount=   s.toString().length();
                 if(cardcount>=16) {
                    boolean cardnumbervalid=   validateCreditCardNumber(s.toString());
                    if(cardnumbervalid) {
                        cardvalidtesting.setText("Valid Card");
                        cardvalidtesting.setTextColor(ContextCompat.getColor(context,R.color.green));
                    }
                    else {
                        cardvalidtesting.setText("Invalid Card");
                        cardvalidtesting.setTextColor(ContextCompat.getColor(context,R.color.red));
                    }
                }
               else if(cardcount>0 &&cardcount<16) {
                     cardvalidtesting.setText("Invalid Card");
                     cardvalidtesting.setTextColor(ContextCompat.getColor(context,R.color.red));
                }

                else {
                    cardvalidtesting.setText("");

                }


                }

            @Override
            public void afterTextChanged(Editable s) {

            }
        });

Answer 5

My solution with jQuery:

function detectCreditCardType() {
    var type = new Array;
    type[1] = '^4[0-9]{12}(?:[0-9]{3})?$';      // visa
    type[2] = '^5[1-5][0-9]{14}$';              // mastercard
    type[3] = '^6(?:011|5[0-9]{2})[0-9]{12}$';  // discover
    type[4] = '^3[47][0-9]{13}$';               // amex

    var ccnum = $('.creditcard').val().replace(/[^\d.]/g, '');
    var returntype = 0;

    $.each(type, function(idx, re) {
        var regex = new RegExp(re);
        if(regex.test(ccnum) && idx>0) {
            returntype = idx;
        }
    });

    return returntype;
}

In case 0 is returned, credit card type is undetected.

"creditcard" class should be added to the credit card input field.

Answer 6

The regular expression rules that match the respective card vendors:

• (4\d{12}(?:\d{3})?) for VISA.
• (5[1-5]\d{14}) for MasterCard.
• (3[47]\d{13}) for AMEX.
• ((?:5020|5038|6304|6579|6761)\d{12}(?:\d\d)?) for Maestro.
• (3(?:0[0-5]|[68][0-9])[0-9]{11}) for Diners Club.
• (6(?:011|5[0-9]{2})[0-9]{12}) for Discover.
• (35[2-8][89]\d\d\d{10}) for JCB.