How do you detect Credit card type based on number

Question

I'm trying to figure out how to detect the type of credit card based purely on its number. Does anyone know of a definitive, reliable way to find this?

Answer 1

The credit/debit card number is referred to as a PAN, or Primary Account Number. The first six digits of the PAN are taken from the IIN, or Issuer Identification Number, belonging to the issuing bank (IINs were previously known as BIN — Bank Identification Numbers — so you may see references to that terminology in some documents). These six digits are subject to an international standard, ISO/IEC 7812, and can be used to determine the type of card from the number.

Unfortunately the actual ISO/IEC 7812 database is not publicly available, however there are unofficial lists, both commercial and free, including on Wikipedia.

Anyway, to detect the type from the number, you can use a regular expression like the ones below: Credit for original expressions

Visa: ^4[0-9]{6,}$ Visa card numbers start with a 4.

MasterCard: ^5[1-5][0-9]{5,}|222[1-9][0-9]{3,}|22[3-9][0-9]{4,}|2[3-6][0-9]{5,}|27[01][0-9]{4,}|2720[0-9]{3,}$ Before 2016, MasterCard numbers start with the numbers 51 through 55, but this will only detect MasterCard credit cards; there are other cards issued using the MasterCard system that do not fall into this IIN range. In 2016, they will add numbers in the range (222100-272099).

American Express: ^3[47][0-9]{5,}$ American Express card numbers start with 34 or 37.

Diners Club: ^3(?:0[0-5]|[68][0-9])[0-9]{4,}$ Diners Club card numbers begin with 300 through 305, 36 or 38. There are Diners Club cards that begin with 5 and have 16 digits. These are a joint venture between Diners Club and MasterCard, and should be processed like a MasterCard.

Discover: ^6(?:011|5[0-9]{2})[0-9]{3,}$ Discover card numbers begin with 6011 or 65.

JCB: ^(?:2131|1800|35[0-9]{3})[0-9]{3,}$ JCB cards begin with 2131, 1800 or 35.

Unfortunately there are a number of card types processed with the MasterCard system that do not live in MasterCard’s IIN range (numbers starting 51...55); the most important case is that of Maestro cards, many of which have been issued from other banks’ IIN ranges and so are located all over the number space. As a result, it may be best to assume that any card that is not of some other type you accept must be a MasterCard.

Important: card numbers do vary in length; for instance, Visa has in the past issued cards with 13 digit PANs and cards with 16 digit PANs. Visa’s documentation currently indicates that it may issue or may have issued numbers with between 12 and 19 digits. Therefore, you should not check the length of the card number, other than to verify that it has at least 7 digits (for a complete IIN plus one check digit, which should match the value predicted by the Luhn algorithm).

One further hint: before processing a cardholder PAN, strip any whitespace and punctuation characters from the input. Why? Because it’s typically much easier to enter the digits in groups, similar to how they’re displayed on the front of an actual credit card, i.e.

4444 4444 4444 4444

is much easier to enter correctly than

4444444444444444

There’s really no benefit in chastising the user because they’ve entered characters you don't expect here.

This also implies making sure that your entry fields have room for at least 24 characters, otherwise users who enter spaces will run out of room. I’d recommend that you make the field wide enough to display 32 characters and allow up to 64; that gives plenty of headroom for expansion.

Here's an image that gives a little more insight:

UPDATE (2014): The checksum method no longer appears to be a valid way of verifying a card's authenticity as noted in the comments on this answer.

UPDATE (2016): Mastercard is to implement new BIN ranges starting Ach Payment.

Answer 2

  public string GetCreditCardType(string CreditCardNumber)
    {
        Regex regVisa = new Regex("^4[0-9]{12}(?:[0-9]{3})?$");
        Regex regMaster = new Regex("^5[1-5][0-9]{14}$");
        Regex regExpress = new Regex("^3[47][0-9]{13}$");
        Regex regDiners = new Regex("^3(?:0[0-5]|[68][0-9])[0-9]{11}$");
        Regex regDiscover = new Regex("^6(?:011|5[0-9]{2})[0-9]{12}$");
        Regex regJCB= new Regex("^(?:2131|1800|35\\d{3})\\d{11}$");


        if(regVisa.IsMatch(CreditCardNumber))
            return "VISA";
       else if (regMaster.IsMatch(CreditCardNumber))
            return "MASTER";
      else  if (regExpress.IsMatch(CreditCardNumber))
            return "AEXPRESS";
       else if (regDiners.IsMatch(CreditCardNumber))
            return "DINERS";
       else if (regDiscover.IsMatch(CreditCardNumber))
            return "DISCOVERS";
       else   if (regJCB.IsMatch(CreditCardNumber))
            return "JCB";
       else
        return "invalid";
    }

Here is the function to check Credit card type using Regex , c#

Answer 3

Swift 2.1 Version of Usman Y's answer. Use a print statement to verify so call by some string value

print(self.validateCardType(self.creditCardField.text!))

func validateCardType(testCard: String) -> String {

    let regVisa = "^4[0-9]{12}(?:[0-9]{3})?$"
    let regMaster = "^5[1-5][0-9]{14}$"
    let regExpress = "^3[47][0-9]{13}$"
    let regDiners = "^3(?:0[0-5]|[68][0-9])[0-9]{11}$"
    let regDiscover = "^6(?:011|5[0-9]{2})[0-9]{12}$"
    let regJCB = "^(?:2131|1800|35\\d{3})\\d{11}$"


    let regVisaTest = NSPredicate(format: "SELF MATCHES %@", regVisa)
    let regMasterTest = NSPredicate(format: "SELF MATCHES %@", regMaster)
    let regExpressTest = NSPredicate(format: "SELF MATCHES %@", regExpress)
    let regDinersTest = NSPredicate(format: "SELF MATCHES %@", regDiners)
    let regDiscoverTest = NSPredicate(format: "SELF MATCHES %@", regDiscover)
    let regJCBTest = NSPredicate(format: "SELF MATCHES %@", regJCB)


    if regVisaTest.evaluateWithObject(testCard){
        return "Visa"
    }
    else if regMasterTest.evaluateWithObject(testCard){
        return "MasterCard"
    }

    else if regExpressTest.evaluateWithObject(testCard){
        return "American Express"
    }

    else if regDinersTest.evaluateWithObject(testCard){
        return "Diners Club"
    }

    else if regDiscoverTest.evaluateWithObject(testCard){
        return "Discover"
    }

    else if regJCBTest.evaluateWithObject(testCard){
        return "JCB"
    }

    return ""

}

Answer 4

The first six digits of a card number (including the initial MII digit) are known as the issuer identification number (IIN). These identify the card issuing institution that issued the card to the card holder. The rest of the number is allocated by the card issuer. The card number's length is its number of digits. Many card issuers print the entire IIN and account number on their card.

Based on the above facts I would like to keep a snippet of JAVA code to identify card brand.

Sample card types

public static final String AMERICAN_EXPRESS = "American Express";
public static final String DISCOVER = "Discover";
public static final String JCB = "JCB";
public static final String DINERS_CLUB = "Diners Club";
public static final String VISA = "Visa";
public static final String MASTERCARD = "MasterCard";
public static final String UNKNOWN = "Unknown";

Card Prefixes

// Based on http://en.wikipedia.org/wiki/Bank_card_number#Issuer_identification_number_.28IIN.29
public static final String[] PREFIXES_AMERICAN_EXPRESS = {"34", "37"};
public static final String[] PREFIXES_DISCOVER = {"60", "62", "64", "65"};
public static final String[] PREFIXES_JCB = {"35"};
public static final String[] PREFIXES_DINERS_CLUB = {"300", "301", "302", "303", "304", "305", "309", "36", "38", "39"};
public static final String[] PREFIXES_VISA = {"4"};
public static final String[] PREFIXES_MASTERCARD = {
        "2221", "2222", "2223", "2224", "2225", "2226", "2227", "2228", "2229",
        "223", "224", "225", "226", "227", "228", "229",
        "23", "24", "25", "26",
        "270", "271", "2720",
        "50", "51", "52", "53", "54", "55"
    };

Check to see if the input number has any of the given prefixes.

public String getBrand(String number) {

String evaluatedType;
if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_AMERICAN_EXPRESS)) {
    evaluatedType = AMERICAN_EXPRESS;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_DISCOVER)) {
    evaluatedType = DISCOVER;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_JCB)) {
    evaluatedType = JCB;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_DINERS_CLUB)) {
    evaluatedType = DINERS_CLUB;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_VISA)) {
    evaluatedType = VISA;
} else if (StripeTextUtils.hasAnyPrefix(number, PREFIXES_MASTERCARD)) {
    evaluatedType = MASTERCARD;
} else {
    evaluatedType = UNKNOWN;
}
    return evaluatedType;
}

Finally, The Utility method

/**
  * Check to see if the input number has any of the given prefixes.
  *
  * @param number the number to test
  * @param prefixes the prefixes to test against
  * @return {@code true} if number begins with any of the input prefixes
*/

public static boolean hasAnyPrefix(String number, String... prefixes) {
  if (number == null) {
       return false;
  }
   for (String prefix : prefixes) {
       if (number.startsWith(prefix)) {
       return true;
    }
  }
     return false;
}

Reference

• Stripe Card Builder

Answer 5

Check this out:

http://www.breakingpar.com/bkp/home.nsf/0/87256B280015193F87256CC70060A01B

function isValidCreditCard(type, ccnum) {
/* Visa: length 16, prefix 4, dashes optional.
Mastercard: length 16, prefix 51-55, dashes optional.
Discover: length 16, prefix 6011, dashes optional.
American Express: length 15, prefix 34 or 37.
Diners: length 14, prefix 30, 36, or 38. */

  var re = new Regex({ "visa": "/^4\d{3}-?\d{4}-?\d{4}-?\d",
                       "mc": "/^5[1-5]\d{2}-?\d{4}-?\d{4}-?\d{4}$/",
                       "disc": "/^6011-?\d{4}-?\d{4}-?\d{4}$/",
                       "amex": "/^3[47]\d{13}$/",
                       "diners": "/^3[068]\d{12}$/"}[type.toLowerCase()])

   if (!re.test(ccnum)) return false;
   // Remove all dashes for the checksum checks to eliminate negative numbers
   ccnum = ccnum.split("-").join("");
   // Checksum ("Mod 10")
   // Add even digits in even length strings or odd digits in odd length strings.
   var checksum = 0;
   for (var i=(2-(ccnum.length % 2)); i<=ccnum.length; i+=2) {
      checksum += parseInt(ccnum.charAt(i-1));
   }
   // Analyze odd digits in even length strings or even digits in odd length strings.
   for (var i=(ccnum.length % 2) + 1; i<ccnum.length; i+=2) {
      var digit = parseInt(ccnum.charAt(i-1)) * 2;
      if (digit < 10) { checksum += digit; } else { checksum += (digit-9); }
   }
   if ((checksum % 10) == 0) return true; else return false;
}

Answer 6

Compact javascript version

    var getCardType = function (number) {
        var cards = {
            visa: /^4[0-9]{12}(?:[0-9]{3})?$/,
            mastercard: /^5[1-5][0-9]{14}$/,
            amex: /^3[47][0-9]{13}$/,
            diners: /^3(?:0[0-5]|[68][0-9])[0-9]{11}$/,
            discover: /^6(?:011|5[0-9]{2})[0-9]{12}$/,
            jcb: /^(?:2131|1800|35\d{3})\d{11}$/
        };
        for (var card in cards) {
            if (cards[card].test(number)) {
                return card;
            }
        }
    };