What does the “|” (single pipe) do in JavaScript?

2019-01-01 01:01发布

console.log(0.5 | 0); // 0
console.log(-1 | 0);  // -1
console.log(1 | 0);   // 1

Why does 0.5 | 0 return zero, but any integer (including negative) returns the input integer? What does the single pipe ("|") do?

标签: javascript
4条回答
孤独寂梦人
2楼-- · 2019-01-01 01:28

This example will help you.

 
    var testPipe = function(input) { 
       console.log('input => ' + input);
       console.log('single pipe | => ' + (input | 'fallback'));
       console.log('double pipe || => ' + (input || 'fallback'));
       console.log('-------------------------');
    };

    testPipe();
    testPipe('something'); 
    testPipe(50);
    testPipe(0);
    testPipe(-1);
    testPipe(true);
    testPipe(false);

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美炸的是我
3楼-- · 2019-01-01 01:35

This is a bitwise or.
Since bitwise operations only make sense on integers, 0.5 is truncated.

0 | x is x, for any x.

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大哥的爱人
4楼-- · 2019-01-01 01:39

A single pipe is a bit-wise OR.

Performs the OR operation on each pair of bits. a OR b yields 1 if either a or b is 1.

JavaScript truncates any non-integer numbers in bitwise operations, so its computed as 0|0, which is 0.

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妖精总统
5楼-- · 2019-01-01 01:40

Bit comparison is so simple it's almost incomprehensible ;) Check out this "nybble"

   8 4 2 1
   -------
   0 1 1 0 = 6  (4 + 2)
   1 0 1 0 = 10 (8 + 2)
   =======
   1 1 1 0 = 14 (8 + 4 + 2)

Bitwise ORing 6 and 10 will give you 14:

   alert(6 | 10); // should show 14

Terribly confusing!

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