Custom date format with jQuery validation plugin

Question

How can I specify a custom date formate to be validated with the Validation Plugin for jQuery?

Answer 1

Check out: jQuery Masked Input Plugin

Answer 2

You can create your own custom validation method using the addMethod function. Say you wanted to validate "dd/mm/yyyy":

$.validator.addMethod(
    "australianDate",
    function(value, element) {
        // put your own logic here, this is just a (crappy) example
        return value.match(/^\d\d?\/\d\d?\/\d\d\d\d$/);
    },
    "Please enter a date in the format dd/mm/yyyy."
);

And then on your form add:

$('#myForm')
    .validate({
        rules : {
            myDate : {
                australianDate : true
            }
        }
    })
;

Answer 3

This is me combining/modifying previous posts to achieve my desired result:

        // Override built-in date validator
        $.validator.addMethod(
            "date",
            function (value, element) {
                //Return            NB: isRequired is not checked at this stage
                return (value=="")? true : isDate(value);
            },
            "* invalid"
        );

Add Date validation after your validation config. I.e. after calling the $(form).validate({ ... }) method.

        //Add date validation (if applicable)
        $('.date', $(frmPanelBtnId)).each(function () {
            $(this).rules('add', {
                date: true
            });
        });

Finally, the main isDate Javascript function modified for UK Date Format

//Validates a date input -- http://jquerybyexample.blogspot.com/2011/12/validate-date-    using-jquery.html
function isDate(txtDate) {
    var currVal = txtDate;
    if (currVal == '')
       return false;

  //Declare Regex  
  var rxDatePattern = /^(\d{1,2})(\/|-)(\d{1,2})(\/|-)(\d{4})$/;
  var dtArray = currVal.match(rxDatePattern); // is format OK?

  if (dtArray == null)
      return false;

   //Checks for dd/mm/yyyy format.
   var dtDay = dtArray[1];
   var dtMonth = dtArray[3];
   var dtYear = dtArray[5];

  if (dtMonth < 1 || dtMonth > 12)
      return false;
  else if (dtDay < 1 || dtDay > 31)
      return false;
  else if ((dtMonth == 4 || dtMonth == 6 || dtMonth == 9 || dtMonth == 11) && dtDay == 31)
      return false;
  else if (dtMonth == 2) {
      var isleap = (dtYear % 4 == 0 && (dtYear % 100 != 0 || dtYear % 400 == 0));
      if (dtDay > 29 || (dtDay == 29 && !isleap))
          return false;
  }

  return true;
}

Answer 4

I personally use the very good http://www.datejs.com/ library.

Docco here: http://code.google.com/p/datejs/wiki/APIDocumentation

You can use the following to get your Australian format and will validate the leap day 29/02/2012 and not 29/02/2011:

jQuery.validator.addMethod("australianDate", function(value, element) { 
    return Date.parseExact(value, "d/M/yyyy");
});

$("#myForm").validate({
   rules : {
      birth_date : { australianDate : true }
   }
});

I also use the masked input plugin to standardise the data http://digitalbush.com/projects/masked-input-plugin/

$("#birth_date").mask("99/99/9999");

Answer 5

$.validator.addMethod("mydate", function (value, element) {

        return this.optional(element) || /^(\d{4})(-|\/)(([0-1]{1})([1-2]{1})|([0]{1})([0-9]{1}))(-|\/)(([0-2]{1})([1-9]{1})|([3]{1})([0-1]{1}))/.test(value);

    });

you can input like yyyy-mm-dd also yyyy/mm/dd

but can't judge the the size of the month sometime Feb just 28 or 29 days.