xpath dates comparison

Question

I'm trying to filter elements based on an attribute that is a date in the format yyyy-MM-dd.

My XML looks like this:

<?xml version="1.0" encoding="utf-8"?>
<root>
  <article title="wired" pub-date="2010-11-22" />
  <article title="Plus 24" pub-date="2010-11-22" />
  <article title="Finance" pub-date="2010-10-25" />
</root>

My xpath attempt:

'//article[xs:date(./@pub-date) > xs:date("2010-11-15")]'

Using xpath 2.0 - would avoid adding a schema unless absolutely necessary.

From comments:

I believe I must be missing something then. Is it possible that I need to specify something else for xs:date to work? Maybe a xs: namespace definition?

Answer 1

In both XPath 1.0 and 2.0 you can use:

//article[number(translate(@pub-date,'-','')) > 20101115]

Your XPath 2.0 expression is correct, using Saxon 9.0.3 this transformation:

<xsl:stylesheet version="2.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema">

    <xsl:template match="/">
      <xsl:sequence select="//article[xs:date(./@pub-date) > xs:date('2010-11-15')]"/>
    </xsl:template>
</xsl:stylesheet>

when applied on the provided XML document:

<root>
  <article title="wired" pub-date="2010-11-22" />
  <article title="Plus 24" pub-date="2010-11-22" />
  <article title="Finance" pub-date="2010-10-25" />
</root>

produces the wanted, correct result:

<article title="wired" pub-date="2010-11-22"/>
<article title="Plus 24" pub-date="2010-11-22"/>

Answer 2

<cfset startdatetime = Now() >
<cfset nNow = LSParseNumber(DateFormat(DateAdd('n', -15,startdatetime),'yyyyMMddHHmm')) >

number(substring(concat(translate(text(),'-: ',''),'0000000000000000'),1,12))<=#nNow#