I have comma separated list of regular expressions:
.{8},[0-9],[^0-9A-Za-z ],[A-Z],[a-z]
I have done a split on the comma. Now I'm trying to match this regex against a generated password. The problem is that Pattern.compile
does not like square brackets that is not escaped. Can some please give me a simple function that takes a string like so: [0-9]
and returns the escaped string \[0-9\]
.
For some reason, the above answer didn't work for me. For those like me who come after, here is what I found.
I was expecting a single backslash to escape the bracket, however, you must use two if you have the pattern stored in a string. The first backslash escapes the second one into the string, so that what regex sees is
\]
. Since regex just sees one backslash, it uses it to escape the square bracket.In regex, that will match a single closing square bracket.
If you're trying to match a newline, for example though, you'd only use a single backslash. You're using the string escape pattern to insert a newline character into the string. Regex doesn't see
\n
- it sees the newline character, and matches that. You need two backslashes because it's not a string escape sequence, it's a regex escape sequence.You can use the \Q and \E special characters...anything between \Q and \E is automatically escaped.
You can use
Pattern.quote(String)
.From the docs:
Pattern.compile()
likes square brackets just fine. If you take the stringand split it on commas, you end up with five perfectly valid regexes: the first one matches eight non-line-separator characters, the second matches an ASCII digit, and so on. Unless you really want to match strings like
".{8}"
and"[0-9]"
, I don't see why you would need to escape anything.