PHP Regex Replace Image SRC Attribute

2019-08-06 05:03发布

I'm trying to find a regular expression that would allow me replace the SRC attribute in an image. Here is what I have:

function getURL($matches) {
  global $rootURL;
  return $rootURL . "?type=image&URL=" . base64_encode($matches['1']);
}

$contents = preg_replace_callback("/<img[^>]*src *= *[\"']?([^\"']*)/i", getURL, $contents);

For the most part, this works well, except that anything before the src=" attribute is eliminated when $contents is echoed to the screen. In the end, SRC is updated properly and all of the attributes after the updated image URL are returned to the screen.

I am not interested in using a DOM or XML parsing library, since this is such a small application.

How can I fix the regex so that only the value for SRC is updated?

Thank you for your time!

2条回答
Root(大扎)
2楼-- · 2019-08-06 05:54

Do another grouping and prepend it to the return value?

function getURL($matches) {
  global $rootURL;
  return $matches[1] . $rootURL . "?type=image&URL=" . base64_encode($matches['2']);
}

$contents = preg_replace_callback("/(<img[^>]*src *= *[\"']?)([^\"']*)/i", getURL, $contents);
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手持菜刀,她持情操
3楼-- · 2019-08-06 05:56

Use a lazy star instead of a greedy one.

This may be your problem:

/<img[^>]*src *= *[\"']?([^\"']*)/
         ^

Change it to:

/<img[^>]*?src *= *[\"']?([^\"']*)/

This way, the [^>]* matches the smallest possible number of your bracket expression, rather than the largest possible.

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