I want to receive the following HTTP
request in PHP:
Content-type: multipart/form-data;boundary=main_boundary
--main_boundary
Content-type: text/xml
<?xml version='1.0'?>
<content>
Some content goes here
</content>
--main_boundary
Content-type: multipart/mixed;boundary=sub_boundary
--sub_boundary
Content-type: application/octet-stream
File A contents
--sub_boundary
Content-type: application/octet-stream
File B contents
--sub_boundary
--main_boundary--
(Note: I have indented the sub-parts only to make it more readable for this post.)
I'm not very fluent in PHP and would like to get some help/pointers to figure out how to receive this kind of multipart form request in PHP code. I have once written some code where I received a standard HTML form and then I could access the form elements by using their name as index key in the $HTTP_GET_VARS
array, but in this case there are no form element names, and the form data parts are not linear (i.e. sub parts = multilevel array).
Grateful for any help!
/Robert
$HTTP_GET_VARS
,$HTTP_POST_VARS
, etc. is an obsolete notation, you should be using$_GET
,$_POST
, etc.Now, the file contents should be in the
$_FILES
global array, whereas, if there are no element names, I'm not sure about whether the rest of the content will show up in$_POST
. Anyway, ifalways_populate_raw_post_data
setting is true in php.ini, the data should be in$HTTP_RAW_POST_DATA
. Also, the whole request should show up when reading php://input.You should note:
“php://input allows you to read raw POST data. It is a less memory intensive alternative to $HTTP_RAW_POST_DATA and does not need any special php.ini directives. php://input is not available with enctype=”multipart/form-data”
From php manual... so it seems php://input is not available
Cannot comment yet but this is intened to complement pilsetnieks answer
Uploadeds files will be accessible through the $_FILE global variable, other parameters will be accessible trough the $_GET global variable.