Understanding PIVOT function in T-SQL

2018-12-31 22:20发布

I am very new to SQL.

I have a table like this:

ID | TeamID | UserID | ElementID | PhaseID | Effort
-----------------------------------------------------
1  |   1    |  1      |   3       |  5     |   6.74
2  |   1    |  1      |   3       |  6     |   8.25
3  |   1    |  1      |   4       |  1     |   2.23
4  |   1    |  1      |   4       |  5     |   6.8
5  |   1    |  1      |   4       |  6     |   1.5

And I was told to get data like this

ElementID | PhaseID1 | PhaseID5 | PhaseID6
--------------------------------------------
    3     |   NULL   |   6.74   |   8.25
    4     |   2.23   |   6.8    |   1.5

I understand I need to use PIVOT function. But can't understand it clearly. It would be great help if somebody can explain it in above case.(or any alternatives if any)

5条回答
旧时光的记忆
2楼-- · 2018-12-31 22:55

These are the very basic pivot example kindly go through that.

SQL SERVER – PIVOT and UNPIVOT Table Examples

Example from above link for the product table:

SELECT PRODUCT, FRED, KATE
FROM (
SELECT CUST, PRODUCT, QTY
FROM Product) up
 PIVOT (SUM(QTY) FOR CUST IN (FRED, KATE)) AS pvt
ORDER BY PRODUCT

renders:

 PRODUCT FRED  KATE
 --------------------
 BEER     24    12
 MILK      3     1
 SODA   NULL     6
 VEG    NULL     5

Similar examples can be found in the blog post Pivot tables in SQL Server. A simple sample

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查无此人
3楼-- · 2018-12-31 23:01

A PIVOT used to rotate the data from one column into multiple columns.

For your example here is a STATIC Pivot meaning you hard code the columns that you want to rotate:

create table temp
(
  id int,
  teamid int,
  userid int,
  elementid int,
  phaseid int,
  effort decimal(10, 5)
)

insert into temp values (1,1,1,3,5,6.74)
insert into temp values (2,1,1,3,6,8.25)
insert into temp values (3,1,1,4,1,2.23)
insert into temp values (4,1,1,4,5,6.8)
insert into temp values (5,1,1,4,6,1.5)

select elementid
  , [1] as phaseid1
  , [5] as phaseid5
  , [6] as phaseid6
from
(
  select elementid, phaseid, effort
  from temp
) x
pivot
(
  max(effort)
  for phaseid in([1], [5], [6])
)p

Here is a SQL Demo with a working version.

This can also be done through a dynamic PIVOT where you create the list of columns dynamically and perform the PIVOT.

DECLARE @cols AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX);

select @cols = STUFF((SELECT distinct ',' + QUOTENAME(c.phaseid) 
            FROM temp c
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

set @query = 'SELECT elementid, ' + @cols + ' from 
            (
                select elementid, phaseid, effort
                from temp
           ) x
            pivot 
            (
                 max(effort)
                for phaseid in (' + @cols + ')
            ) p '


execute(@query)

The results for both:

ELEMENTID   PHASEID1    PHASEID5    PHASEID6
3           Null        6.74        8.25
4           2.23        6.8         1.5
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梦寄多情
4楼-- · 2018-12-31 23:03

To set Compatibility error

use this before using pivot function

ALTER DATABASE [dbname] SET COMPATIBILITY_LEVEL = 100  
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裙下三千臣
5楼-- · 2018-12-31 23:11
    SELECT <non-pivoted column>,
    [first pivoted column] AS <column name>,
    [second pivoted column] AS <column name>,
    ...
    [last pivoted column] AS <column name>
FROM
    (<SELECT query that produces the data>)
    AS <alias for the source query>
PIVOT
(
    <aggregation function>(<column being aggregated>)
FOR
[<column that contains the values that will become column headers>]
    IN ( [first pivoted column], [second pivoted column],
    ... [last pivoted column])
) AS <alias for the pivot table>
<optional ORDER BY clause>;

USE AdventureWorks2008R2 ;
GO
SELECT DaysToManufacture, AVG(StandardCost) AS AverageCost 
FROM Production.Product
GROUP BY DaysToManufacture;

    DaysToManufacture          AverageCost
0                          5.0885
1                          223.88
2                          359.1082
4                          949.4105

    -- Pivot table with one row and five columns
SELECT 'AverageCost' AS Cost_Sorted_By_Production_Days, 
[0], [1], [2], [3], [4]
FROM
(SELECT DaysToManufacture, StandardCost 
    FROM Production.Product) AS SourceTable
PIVOT
(
AVG(StandardCost)
FOR DaysToManufacture IN ([0], [1], [2], [3], [4])
) AS PivotTable;




Here is the result set.
Cost_Sorted_By_Production_Days    0         1         2           3       4       
AverageCost                       5.0885    223.88    359.1082    NULL    949.4105
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浅入江南
6楼-- · 2018-12-31 23:12

I was new to this and I create a nice post about it... My problem was understanding how to apply aggregation correctly and here is my post: http://jaider.net/posts/1176-pivot-in-sql-server-correct-aggregated-results/

In @bluefeet solution, It's important to mention that elementid is the key column of your "invisible" Group By. Additionally, you can replace elementid or add more columns such as userid.

enter image description here

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