Run multiple reducers on single output from mapper

2019-08-02 11:31发布

I am implementing a left join functionality using map reduce. Left side is having around 600 million records and right side is having around 23 million records. In mapper I am making the keys using the columns used in left join condition and passing the key-value output from mapper to reducer. I am getting performance issue because of few mapper keys for which number of values in both the tables are high (eg. 456789 and 78960 respectively). Even though other reducers finish their job, these reducers keep running for longer time. Is there any way that multiple reducers can work on the same key-value output from mapper in parallel to better the performance?

This is the Hive query that i want to optimize.

select distinct 
        a.sequence, 
        a.fr_nbr, 
        b.to_nbr, 
        a.fr_radius,
        a.fr_zip, 
        a.latitude as fr_latitude, 
        a.longitude as fr_longitude, 
        a.to_zip, 
        b.latitude as to_latitude, 
        b.longitude as to_longitude,
        ((2 * asin( sqrt( cos(radians(a.latitude)) * cos(radians(b.latitude)) * pow(sin(radians((a.longitude - b.longitude)/2)), 2) + pow(sin(radians((a.latitude - b.latitude)/2)), 2) ) )) * 6371 * 0.621371) as distance,
        a.load_year, 
        a.load_month
from common.sb_p1 a LEFT JOIN common.sb__temp0u b    
        on a.to_zip=b.zip
            and a.load_year=b.load_year
            and a.load_month=b.load_month
where   b.correction = 0 
        and a.fr_nbr <> b.to_nbr 
        and ((2 * asin( sqrt( cos(radians(a.latitude)) * cos(radians(b.latitude)) * pow(sin(radians((a.longitude - b.longitude)/2)), 2) + pow(sin(radians((a.latitude - b.latitude)/2)), 2) ) )) * 6371 * 0.621371 <= a.fr_radius)

Any other solution will also be appreciated.

2条回答
Emotional °昔
2楼-- · 2019-08-02 12:16

You can also consider using HiveQL for this. Its pretty much meant for situations like the one you have mentioned above and takes care of complexity of map reduce implementation.

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Ridiculous、
3楼-- · 2019-08-02 12:22

Split the skewed keys using UNION ALL:

select * from table1 a left join table2 b on a.key=b.key
where a.key not in (456789,78960)
union all
select * from table1 a left join table2 b on a.key=b.key
where a.key = 456789
union all
select * from table1 a left join table2 b on a.key=b.key
where a.key = 78960
;

These subqueries will run in parallel, skewed keys will not be distributed to single reducer

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