What does map(&:name) mean in Ruby?

Question

I found this code in a RailsCast:

def tag_names
  @tag_names || tags.map(&:name).join(' ')
end

What does the (&:name) in map(&:name) mean?

Answer 1

While let us also note that ampersand #to_proc magic can work with any class, not just Symbol. Many Rubyists choose to define #to_proc on Array class:

class Array
  def to_proc
    proc { |receiver| receiver.send *self }
  end
end

# And then...

[ 'Hello', 'Goodbye' ].map &[ :+, ' world!' ]
#=> ["Hello world!", "Goodbye world!"]

Ampersand & works by sending to_proc message on its operand, which, in the above code, is of Array class. And since I defined #to_proc method on Array, the line becomes:

[ 'Hello', 'Goodbye' ].map { |receiver| receiver.send( :+, ' world!' ) }

Answer 2

Although we have great answers already, looking through a perspective of a beginner I'd like to add the additional information:

What does map(&:name) mean in Ruby?

This means, that you are passing another method as parameter to the map function. (In reality you're passing a symbol that gets converted into a proc. But this isn't that important in this particular case).

What is important is that you have a method named name that will be used by the map method as an argument instead of the traditional block style.

Answer 3

it means

array.each(&:to_sym.to_proc)

Answer 4

Another cool shorthand, unknown to many, is

array.each(&method(:foo))

which is a shorthand for

array.each { |element| foo(element) }

By calling method(:foo) we took a Method object from self that represents its foo method, and used the & to signify that it has a to_proc method that converts it into a Proc.

This is very useful when you want to do things point-free style. An example is to check if there is any string in an array that is equal to the string "foo". There is the conventional way:

["bar", "baz", "foo"].any? { |str| str == "foo" }

And there is the point-free way:

["bar", "baz", "foo"].any?(&"foo".method(:==))

The preferred way should be the most readable one.

Answer 5

Here :name is the symbol which point to the method name of tag object. When we pass &:name to map, it will treat name as a proc object. For short, tags.map(&:name) acts as:

tags.map do |tag|
  tag.name
end

Answer 6

map(&:name) takes an enumerable object (tags in your case) and runs the name method for each element/tag, outputting each returned value from the method.

It is a shorthand for

array.map { |element| element.name }

which returns the array of element(tag) names