Can I Allocate a Block of Memory with new?

Question

So given this c structure:

typedef struct {
    int* arr1;
    int* arr2;
} myStruct;

This answer described using a single malloc to allocate a myStruct and it's arrays at the same time:

myStruct* p = malloc(sizeof(*p) + 10 * sizeof(*p->arr1) + 10 * num * sizeof(*p->arr2);

if(p != NULL) {
    p->arr1 = (int*)(p + 1);
    p->arr2 = p->arr1 + 10;
}

What I'd like to know is there a similar way to do this with new?
Obviously I want to be able to allocate to a size that I receive at runtime as is done with the C example.

Answer 1

You can allocate a block of memory using new with an array of char, then use placement new to call the constructor on that block of memory.

Answer 2

Is there any reason you want to do it like in the link you provided? A little more context would help. Otherwise I would personally just use a constructor to do that:

    struct myStruct {
        int* arr1;
        int* arr2;
        myStruct(int num)
        {
                arr1 = new int[10];
                arr2 = new int[10*num];
        }
        ~myStruct()
        {
                delete[] arr1;
                delete[] arr2;
        }
};

int main()
{
        int num = 3;
        myStruct* a;
        a = new myStruct(3);
        delete a;
}

Answer 3

In c++ we use new because it calls the constructors of the objects being allocated. So the proper way to achieve what you want is to have the constructor of the structure do the necessary allocations.