{var%20f='http://v.t.sina.com.cn/share/share.php?appkey=1515056452',u=z||d.location,p=['&url=',e(u),'&title=',e(t||d.title),'&source=',e(r),'&sourceUrl=',e(l),'&content=',c||'gb2312','&pic=',e(p||'')].join('');function%20a(){if(!window.open([f,p].join(''),'mb',['toolbar=0,status=0,resizable=1,width=440,height=430,left=',(s.width-440)/2,',top=',(s.height-430)/2].join('')))u.href=[f,p].join('');};if(/Firefox/.test(navigator.userAgent))setTimeout(a,0);else%20a();})(screen,document,encodeURIComponent,'','','https://www.manongdao.com/data/attach/logo/logo.png', '推荐 够拽才男人 的问题《Why does the nested quasiquote not unwrap splice-u》','https://www.manongdao.com/q-923393.html','页面编码gb2312|utf-8默认gb2312'));){kind=link}
Why does the first macro unquote-splicing not produce (quasiquote (unquote (quasiquote 1 2))), but the second example replaces the value?
(define x (list 1 2))
(t '(quasiquote (unquote (quasiquote (unquote-splicing x))))
(quasiquote (quasiquote (unquote (quasiquote (unquote-splicing x))))))
(t '(quasiquote (unquote (quasiquote (unquote (1 2)))))
(quasiquote (quasiquote (unquote (quasiquote (unquote (unquote x)))))))
In the first example
This has 3 quasiquotes and 2 unquotes, so 'x' will not be evaluated.
in the second example
there are 3 quasiquotes and 3 unquotes so 'x' will be replaced by it's value.