So for an assignment I have to generate a random code, and have someone guess the code in the console. Now My problem is that I can't seem to find a way to replace any duplicate characters in the code. The code must range in "ABCDEF", and contain 4 letters. This is what I got so far:
char codeLetters;
String masterCode;
StringBuilder strings = new StringBuilder();
Random random = new Random();
for (int i = 0; i < 4; i++) {
codeLetters = code[random.nextInt(code.length)];
strings.append(codeLetters);
}
masterCode = strings.toString();
String temp = "";
boolean isDuplicate = false;
for (int i = 0; i < masterCode.length(); i++) {
isDuplicate = false;
char comparisonChar = masterCode.charAt(i);
for (int j = i + 1; j < masterCode.length(); j++) {
char nextChar = masterCode.charAt(j);
if (comparisonChar == nextChar) isDuplicate = true;
}
if (!isDuplicate) temp = temp + comparisonChar;
}
masterCode = temp;
System.out.println(masterCode);
it prints either a code consisting out of 2-3 letters, or a code containing 5 or 6 letters, and rarely a correct code with 4 letters. What this code does as far as I know is not add the duplicate characters, but I want it to Replace them instead with another character. Is there someway to replace the characters with another randomly generated char, which is not in the String yet, without using Sets?
It sounds like you only want to use each letter in
code
once? Why don't you set that up from the beginning using anArrayList
, and removing each character if it is randomly selected:Replace your for loop with this one and then you don't need to do any replacing afterwards. This will only insert characters that are not already in the string.