If calling something like input_stream >> i;
where i
is of arithmetic type, throws exception or sets badbit etc., is it guaranteed that i
has not changed?
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Before C++11, the value was left as it was, [reference]:
But after C++11, no. It is set to
0
if extraction fails (same reference):Referring to the cppreference documentation for
std::basic_istream::operator>>
std::num_get::get, std::num_get::do_get
:And then