appendAll - Append a list to all lists within a li

2019-07-27 07:41发布

I'm trying to find a way to append a list to all lists within a list.

Something like:

appendAll([a,b],[[q,w],[z,x]],X).
X = [[a,b,q,w],[a,b,z,x]].

I'm still new to prolog and nested lists are throwing me off quite a bit.

I've been staring at this for a few hours now:

appendAll([], _, []).
appendAll(_, [], []).
appendAll([H1|T1], [H2|T2], X) :-
  append(H1,H2,R),
  appendAll(T1,[H2|T2],X).
  % recurse down to [], and append back up

Any help is much appreciated Thanks!

1条回答
姐就是有狂的资本
2楼-- · 2019-07-27 08:26

What is difficult in programming with Prolog is to get used to and identify the actual recursion patterns behind. In many cases it is best not to think in recursions directly, but rather ask if some simple for all construct might work here.

In this case, you want a relation between a list of lists and another list of lists. Both are of same length, as the elements correspond to each other element-wise.

appendAll(Prefix, Lists, Prefixedlists) :-
    maplist(append(Prefix), Lists, Prefixedlists).

The predicate maplist/3 is defined in many Prolog systems. If not, define it like so in an ISO conforming system:

maplist(_Cont_2, [], []).
maplist(Cont_2, [X|Xs], [Y|Ys]) :-
   call(Cont_2, X, Y),
   maplist(Cont_2, Xs, Ys).

Here is the same, as a plain predicate:

maplist_append(Prefix, [], []).
maplist_append(Prefix, [X|Xs], [Y|Ys]) :-
   append(Prefix, X, Y),
   maplist_append(Prefix, Xs, Ys).
查看更多
登录 后发表回答