I'm using the following code to hide the background MS-Access window from my main application.
Global Const SW_HIDE = 0
Global Const SW_SHOWNORMAL = 1
Global Const SW_SHOWMINIMIZED = 2
Global Const SW_SHOWMAXIMIZED = 3
Private Declare Function apiShowWindow Lib "user32" Alias "ShowWindow" (ByVal hwnd As Long, ByVal nCmdShow As Long) As Long
Function fSetAccessWindow(nCmdShow As Long)
Dim loX As Long
Dim loForm As Form
On Error Resume Next
Set loForm = Screen.ActiveForm
If Err <> 0 Then
loX = apiShowWindow(hWndAccessApp, nCmdShow)
Err.Clear
End If
If nCmdShow = SW_SHOWMINIMIZED And loForm.Modal = True Then
MsgBox "Cannot minimize Access with " _
& (loForm.Caption + " ") _
& "form on screen"
ElseIf nCmdShow = SW_HIDE And loForm.PopUp <> True Then
MsgBox "Cannot hide Access with " _
& (loForm.Caption + " ") _
& "form on screen"
Else
loX = apiShowWindow(hWndAccessApp, nCmdShow)
End If
fSetAccessWindow = (loX <> 0)
End Function
However, I would like to do the same with another database (form) that I'm opening with the following code:
Dim appAccess As Access.Application
Set appAccess = CreateObject("Access.Application")
appAccess.OpenCurrentDatabase "myDatabasePath"
appAccess.DoCmd.OpenForm "myFormName"
Set appAccess = Nothing
How could I make this work from the main application? I guess I could also call my fSetAccessWindow() function from the myFormName form in myDatabasePath database but I would like to do it from the main application that calls that second mdb file.
I'm using Access 2007 to develop Access 2000-2003 MDB databases.
Use the Application.hWndAccessApp Method to retrieve the window handle of the second Access application instance.
Feed that value to the
apiShowWindow()
function.I didn't test this, so unsure whether I overlooked something, but it seems like a reasonable starting point to me.