I want to convert an image from RGBA to YUV422 format. Below is my code:
#include "opencv2/highgui/highgui.hpp"
#include "opencv2/imgproc/imgproc.hpp"
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
using namespace cv;
using namespace std;
#define CLIP(X) ( (X) > 255 ? 255 : (X) < 0 ? 0 : X)
#define RGB2Y(R, G, B) CLIP(( ( 66 * (R) + 129 * (G) + 25 * (B) + 128) >> 8) + 16)
#define RGB2U(R, G, B) CLIP(( ( -38 * (R) - 74 * (G) + 112 * (B) + 128) >> 8) + 128)
#define RGB2V(R, G, B) CLIP(( ( 112 * (R) - 94 * (G) - 18 * (B) + 128) >> 8) + 128)
int main(int argc, char *argv[])
{
Mat in_img, in_RGB, out_yuv;
in_img = imread(argv[1],1);
if(!in_img.data)
{
printf("Failed to load the image ... %s\n!", argv[1]);
return -1;
}
short imgwidth = in_img.cols;
short imgheight = in_img.rows;
cvtColor(in_img, in_RGB, CV_BGR2RGB);
out_yuv.create(imgheight, imgwidth, CV_16U);
imwrite("RGB.jpg",in_RGB);
for(int i = 0; i< imgheight; i++)
for(int j = 0; j< imgwidth; j = j+2) {
unsigned int val = in_RGB.at<unsigned int>(i,j);
/*********** for 1st pixel ***********/
unsigned int tmp = val;
unsigned char B = (unsigned char)(((tmp<<16) >> 24) | 0x000000ff ); //Extracting B channel data
tmp = val;
unsigned char G = (unsigned char)(((tmp<<8) >> 24) | 0x000000ff ); //Extracting G channel data
tmp = val;
unsigned char R = (unsigned char)((tmp >> 24) | 0x000000ff ); //Extracting R channel data
unsigned char Y1 = RGB2Y(R, G, B);
unsigned char U = RGB2U(R, G, B);
unsigned char V = RGB2V(R, G, B);
/*********** for 2nd pixel ***********/
unsigned int val1 = in_RGB.at<unsigned int>(i,j+1);
unsigned int tmp1 = val1;
unsigned char B1 = (unsigned char)(((tmp1<<16) >> 24) | 0x000000ff );
tmp1 = val1;
unsigned char G1 = (unsigned char)(((tmp1<<8) >> 24) | 0x000000ff );
tmp1 = val1;
unsigned char R1 = (unsigned char)((tmp1 >> 24) | 0x000000ff );
unsigned char Y2 = RGB2Y(R, G, B);
/********** writing into out image in U-Y1-V-Y2 format *********************/
unsigned short p1 = ((U << 8) | Y1) ;
unsigned short p2 = ((V << 8) | Y2) ;
out_yuv.at<unsigned short>(i,j) = p1;
out_yuv.at<unsigned short>(i,j+1) = p2;
}
imwrite("YUV422.png",out_yuv);
return 0;
}
But am not getting a proper output image. I also tried writing it in Y1-U-Y2-V format, still same output. What could be wrong with the above code or is it the output image format(.png/.jpg) that's creating the probelm? (cv::imwrite doesn't allow saving in .yuv format)
Several issues here :
imwrite
considersCV_16U
to be mono channel.Edit:
Note that raw pixels acronyms are kinda big endian, ie the leftmost value is the least significant byte in memory (most of the time, video people love confusion)
R = RGB[0]
,G = RGB[1]
,B = RGB[2]
,A = RGB[3]
p
meansp[0]
is Y0,p[1]
is U,p[2]
is Y1,p[3]
is VYou are doing the exact opposite with your shifts:)
Edit 2: If your image is still scrambled, you seem to be willing to write following the planar format (YUV422P aka
YV16
). Planar format means each channel is on a separate, contiguous plane. It is clearer to use a plain old buffer for the target data(unsigned char*
, orstd::vector<unsigned char>
).