I have this code:
<?php
$servername = "Jarvis";
$username = "TonyStark";
$password = "iLoveIronMan";
$dbname = "StarkCompany";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT o.order_id, o.customer_id, op.quantity, op.model FROM oc_order o INNER JOIN oc_order_product op ON o.order_id = op.order_id INNER JOIN oc_product p ON op.product_id = p.product_id WHERE o.order_status_id = 2 AND p.location = 1 ORDER BY o.order_id, op.model";
$file = fopen('../files/in/filename.csv', 'w');
if ($rows = mysqli_query($conn, $sql))
{
while ($row = mysqli_fetch_assoc($rows))
{
fputcsv($file, $row, ';');
}
mysqli_free_result($rows);
}
mysqli_close($conn);
fclose($file);
?>
Now: How can i take for example the SQL value of the table o.order_id and use this value for my filename? The filename should be example(o.order_id).csv. Is this possible?
You can make your life easier by naming the value like this:
then when you handle the rows you can use