How to prevent an object from getting garbage coll

2019-01-10 18:58发布

How to prevent an object from getting garbage collected?

Are there any approaches by finalize or phantom reference or any other approaches?

I was asked this question in an interview. The interviewer suggested that finalize() can be used.

10条回答
欢心
2楼-- · 2019-01-10 19:25

I believe there is a pattern out there for this. Not sure if it the factory pattern. But you have one object that creates all your objects and holds a reference to them. When you are finished with them, you de-reference them in the factory, making the call explicit.

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虎瘦雄心在
3楼-- · 2019-01-10 19:31

Hold a reference. If your object is getting collected prematurely, it is a symptom that you have a bug in the design of your application.

The garbage collector collects only objects to which there is no reference in your application. If there is no object that would naturally reference the collected object, ask yourself why it should be kept alive.

One usecase in which you typically have no references, but want to keep an object is a singleton. In this case, you could use a static variable. One possible implementation of a singleton would look like this:

public class Singleton {
  private static Singleton uniqueInstance;

  private Singleton() {
    }

  public static synchronized Singleton getInstance() {
    if (uniqueInstance == null) {
      uniqueInstance = new Singleton();
    }
    return uniqInstance;
  }
}

Edit: Technically, you can store a reference somewhere in your finalizer. This will prevent the object from being collected until the collector determines again that there are no more references. The finalizer will only be called at most once, however, so you must ensure that your object (including its superclasses) need not be finalized after the first collection. I would advise you, however, not to use this technique in actual programs. (It will leave colleagues like me yelling WTF!? ;)

  protected void finalize() throws Throwable {
    MyObjectStore.getInstance().store(this);
    super.finalize(); // questionable, but you should ensure calling it somewhere.
  }
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家丑人穷心不美
4楼-- · 2019-01-10 19:36

If there is still a reference to the object, it won't get garbage collected. If there aren't any references to it, you shouldn't care.

In other words - the garbage collector only collects garbage. Let it do its job.

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家丑人穷心不美
5楼-- · 2019-01-10 19:37

We have three ways to achieve same - 1) Increasing the Heap -Eden space size . 2) Create Singleton class with Static reference . 3) Override finalize() method and never let that object dereference.

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放荡不羁爱自由
6楼-- · 2019-01-10 19:41

I suspect what you might be referring to is if your finalize method stashes away a reference to the object being finalized. In this case (if my reading of the Java Language Spec is correct) the finalize method will never be re-run, but the object will not yet be garbage collected.

This is not the sort of thing one does in real life, except possibly by accident!

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冷血范
7楼-- · 2019-01-10 19:43

The trick answer your interviewer was looking for is probably that he wants you to know that you can prevent garbage collection from removing an object by forcing a memory leak.

Obviously, if you keep a reference to the object in some long-lived context, it won't be collected, but that's not what the OP's recruiter asked about. That's not something which happens in the finalize method.

What you can do to prevent garbage collection from within the finalize method is to write an infinite loop, in which you call Thread.yield();(presumably to keep an empty loop from being optimized away):

@Override
protected void finalize() throws Throwable { 
    while (true) { 
        Thread.yield(); 
    } 
} 

My reference here is an article by Elliot Back, in which describes forcing a memory leak by this method.

Just another way in which finalize methods are evil.

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