This code:
@echo off
echo/|set /p ="Executing backup...."
echo/|set /p =" backup procedure"
... came from Echoing in the same line and produces the below output in a cmd window:
Executing backup....backup procedure
However, I cant seem to find an explanation through google on what the forward slash does to the ¿pipe?
to cause set
's output to be echo
ed to the console / stdout
If anyone could also suggest a good website for learning more about cmd
/ cmd
programs' features like this, it would be appreciated.
Care of https://stackoverflow.com/users/1201210/tenterhook
1) echo prints the result of set /p =... with or without the / before the pipe, so I'm not sure what your question is asking
2) (It will also print set /p =... with random junk after the echo, too, since it's reading the piped stuff and not the arguments it receives.)
I will hence suggest edits to the referenced SO post, to prevent others confusion.
The
echo/
is simply a way of printing only an empty line, instead ofECHO IS ON
for a singleecho
.But in this case it's completly unimportant, as the only use of the echo is for creating some stuff for the pipe, so the set /p will not wait for user input.
But this way to echo text without a linefeed is very inefficient, as a pipe creates two new instances of cmd.exe.
It's much simpler and faster to use
The redirect from
NUL
will also stop the waiting for user input.