How to list all tables & columns names of a linked

2019-07-20 20:16发布

If it's a regular database, i can simply use this query to get a list of all table names and their column names of the database.

use [my_database_name]
GO

SELECT sys.tables.name AS Table_Name, 
       sys.columns.name AS Column_Name, 
       sys.columns.max_length, 
       (schema_id) As Schema_name

FROM sys.tables
    INNER JOIN sys.columns 
        ON sys.tables.OBJECT_ID=sys.columns.object_id

ORDER BY schema_name, sys.tables.name, sys.columns.name

but right now I need to connect to a linked-server database therefore the 'use' can't be used. Is there another way?

4条回答
萌系小妹纸
2楼-- · 2019-07-20 20:37

There is the solution to list:

declare @temp table
(
    col1 varchar(255),
    col2 varchar(255),
    [name] varchar(255),
    [type] varchar(255),
    col3 varchar(255)
)
insert @temp exec sp_tables_ex 'Your_LinkedServer_Name'
select * from @temp

And also open a cursor:

DECLARE lstTables CURSOR FOR 
        select [name] from @temp
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姐就是有狂的资本
3楼-- · 2019-07-20 20:58

The system stored procedure sp_tables is used to list out the tables available in the current database of the current server. You can use sp_tables_ex for the linked server. The following returns list of tables available in the specified Server:

EXEC sp_tables_ex @table_server = 'MYSQL_DB'
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爷、活的狠高调
4楼-- · 2019-07-20 21:00

To expand slightly on @scsimon's answer...

The (schema_id) As Schema_name is not very useful, as it's really an ID. To get the list of all tables (and their columns) with actual schema names one can use:

SELECT s.name AS schema_name
      ,t.name AS table_Name
      ,c.name AS column_Name
    --,c.max_length
FROM [SERVER].[DB].sys.tables t
JOIN [SERVER].[DB].sys.schemas s ON t.schema_id = s.schema_id
JOIN [SERVER].[DB].sys.columns c ON t.object_id = c.object_id
--WHERE s.name = 'dbo'
ORDER BY s.name, t.name, c.name
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祖国的老花朵
5楼-- · 2019-07-20 21:02

Fully qualify your linked server in your FROM and JOIN, and alias them.

SELECT lst.name AS Table_Name, 
       lsc.name AS Column_Name, 
       lsc.max_length, 
       (schema_id) As Schema_name

FROM [SERVER].[DB].[sys].[tables] lst
    INNER JOIN [SERVER].[DB].[sys].[columns] lsc
        ON lst.OBJECT_ID=lsc.object_id

ORDER BY schema_name, lst.name, lsc.name
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