I would like to return all the results from my prepared query (mysqli) as objects in an array but i cant find a fetchall method or something similar. How do i go about this?
public function getImageResults ($search_term)
{
if (empty($search_term))
return false;
$image_query = $this->db_connection->stmt_init();
$image_query_sql =
"
SELECT
Images.url as url
FROM
Images, ImageSearch, ImageSearchResults
WHERE
ImageSearch.search_string = ? AND
ImageSearchResults.search_id = ImageSearch.id AND
ImageSearchResults.image_id = Images.id AND
Images.deleted = 0 AND
ImageSearch.deleted = 0 AND
ImageSearchResults.deleted = 0
";
if ($image_query->prepare($image_query_sql))
{
$image_query->bind_param('s', $search_term);
$image_query->execute();
$image_query->store_result();
$image_query->bind_result($url);
return //need to return the entire result set here... any ideas?
}
return false;
}
I found this code on the net which kinda works but i get this error when i use it
Notice: Use of undefined constant mysqli_stmt_bind_result - assumed 'mysqli_stmt_bind_result'
private function getresult ($stmt)
{
$result = array();
$metadata = $stmt->result_metadata();
$fields = $metadata->fetch_fields();
for (;;)
{
$pointers = array();
$row = new stdClass();
$pointers[] = $stmt;
foreach ($fields as $field)
{
$fieldname = $field->name;
$pointers[] = &$row->$fieldname;
}
call_user_func_array(mysqli_stmt_bind_result, $pointers);
if (!$stmt->fetch())
break;
$result[] = $row;
}
$metadata->free();
return $result;
}
Hm, you could try something like this, if I remember correctly:
The
mysqli_stmt_bind_result
on this line:should be quoted:
You could also use PDO, an untested example but it should work: