What is double star (eg. NSError **)?

2019-01-10 06:56发布

So, I saw this:

error:(NSError **)error

in the apple doc's. Why two stars? What is the significance?

5条回答
虎瘦雄心在
2楼-- · 2019-01-10 07:22

If it is anything like C then ** means a pointer to a pointer.

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forever°为你锁心
3楼-- · 2019-01-10 07:24

In C, a double star is a pointer to a pointer. There are a couple of reasons to do this. First is that the pointer might be to an array of pointers. Another reason would be to pass a pointer to a function, where the function modifies the pointer (similar to an "out" parameter in other languages).

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我想做一个坏孩纸
4楼-- · 2019-01-10 07:25

A "double star" is a pointer to a pointer. So NSError ** is a pointer to a pointer to an object of type NSError. It basically allows you to return an error object from the function. You can create a pointer to an NSError object in your function (call it *myError), and then do something like this:

*error = myError;

to "return" that error to the caller.


In reply to a comment posted below:

You can't simply use an NSError * because in C, function parameters are passed by value—that is, the values are copied when passed to a function. To illustrate, consider this snippet of C code:

void f(int x)
{
    x = 4;
}

void g(void)
{
    int y = 10;
    f(y);
    printf("%d\n", y);    // Will output "10"
}

The reassignment of x in f() does not affect the argument's value outside of f() (in g(), for example).

Likewise, when a pointer is passed into a function, its value is copied, and re-assigning will not affect the value outside of the function.

void f(int *x)
{
    x = 10;
}

void g(void)
{
    int y = 10;
    int *z = &y;
    printf("%p\n", z);    // Will print the value of z, which is the address of y
    f(z);
    printf("%p\n", z);    // The value of z has not changed!
}

Of course, we know that we can change the value of what z points to fairly easily:

void f(int *x)
{
    *x = 20;
}

void g(void)
{
    int y = 10;
    int *z = &y;
    printf("%d\n", y);    // Will print "10"
    f(z);
    printf("%d\n", y);    // Will print "20"
}

So it stands to reason that, to change the value of what an NSError * points to, we also have to pass a pointer to the pointer.

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我想做一个坏孩纸
5楼-- · 2019-01-10 07:40

In C everything is pass by value. If you want to change the value of something you pass the address of it (which passes the value of the memory address). If you want to change where a pointer points you pass the the addres of the pointer.

Take a look here for a simple explanation.

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Bombasti
6楼-- · 2019-01-10 07:43

The double star (**) notation is not specific to initializing a variable in a class. It is simply a double indirect reference to an object.

  float myFloat; // an object
    float *myFloatPtr; // a pointer to an object
    float **myFloatPtrPtr; // a pointer to a pointer to an object

    myFloat = 123.456; // initialize an object
    myFloatPtr = &myFloat; // initialize a pointer to an object
    myFloatPtrPtr = myFloatPtr; // initialize a pointer to a pointer to an object

    myFloat; // refer to an object
    *myFloatPtr; // refer to an object through a pointer
    **myFloatPtrPtr; // refer to an object through a pointer to a pointer
    *myFloatPtrPtr; // refer to the value of the pointer to the object

Double pointer notation is used where the caller intends that one of its own pointers need to be modified by a function call, so the address of the pointer, instead of the address of the object, is passed to the function.

An example might be the use of a linked list. The caller maintains a pointer to the first node. The caller invokes functions to search, add, and remove. If those operations involve adding or deleting the first node, then the caller's pointer has to change, not the .next pointer in any of the nodes, and you need the address of the pointer to do that.

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