How can I use a Lambda function to call a Glue fun

2019-07-13 15:21发布

I am trying to set up a lambda function that activates a Glue function when a .txt file is uploaded to an S3 bucket, I am using python 3.7

So far I have this:

from __future__ import print_function

import json
import boto3
import urllib

print('Loading function')

s3 = boto3.client('s3') 

def lambda_handler(event, context): # handler
    source_bucket = event['Records'][0]['s3']['bucket']['name']
    key = urllib.parse.quote_plus(event['Records'][0]['s3']['object']['key'].encode('utf8'))
    try:
        # what to put here
    except Exception as e:
        print(e)
        print('Error')
        raise e

But I don't understand how can I call the glue function

2条回答
三岁会撩人
2楼-- · 2019-07-13 15:50

I manage to do it like this:

from __future__ import print_function
import json
import boto3

client = boto3.client('glue')

def lambda_handler(event, context):
    response = client.start_job_run(JobName = 'GLUE_CODE_NAME')

Later I will post the S3 event

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男人必须洒脱
3楼-- · 2019-07-13 15:50

You can configure an S3 Event Notification that will trigger this Lambda function when PUT object actions is called on an S3 prefix.

https://docs.aws.amazon.com/AmazonS3/latest/user-guide/enable-event-notifications.html

This lambda function can then trigger the StartJobRun action of Glue API.

https://docs.aws.amazon.com/glue/latest/webapi/API_StartJobRun.html

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