How to check if a file contains a specific string

Question

I want to check if a file contains a specific string or not in bash. I used this script, but it doesn't work:

 if [[ 'grep 'SomeString' $File' ]];then
   # Some Actions
 fi

What's wrong in my code?

Answer 1

Shortest (correct) version:

grep -q "something" file; [ $? -eq 0 ] && echo "yes" || echo "no"

can be also written as

grep -q "something" file; test $? -eq 0 && echo "yes" || echo "no"

but you dont need to explicitly test it in this case, so the same with:

grep -q "something" file && echo "yes" || echo "no"

Answer 2

if grep -q SomeString "$File"; then
  Some Actions # SomeString was found
fi

You don't need [[ ]] here. Just run the command directly. Add -q option when you don't need the string displayed when it was found.

The grep command returns 0 or 1 in the exit code depending on the result of search. 0 if something was found; 1 otherwise.

$ echo hello | grep hi ; echo $?
1
$ echo hello | grep he ; echo $?
hello
0
$ echo hello | grep -q he ; echo $?
0

You can specify commands as an condition of if. If the command returns 0 in its exitcode that means that the condition is true; otherwise false.

$ if /bin/true; then echo that is true; fi
that is true
$ if /bin/false; then echo that is true; fi
$

As you can see you run here the programs directly. No additional [] or [[]].

Answer 3

##To check for a particular  string in a file

cd PATH_TO_YOUR_DIRECTORY #Changing directory to your working directory
File=YOUR_FILENAME  
if grep -q STRING_YOU_ARE_CHECKING_FOR "$File"; ##note the space after the string you are searching for
then
echo "Hooray!!It's available"
else
echo "Oops!!Not available"
fi

Answer 4

grep -q "something" file
[[ !? -eq 0 ]] && echo "yes" || echo "no"