Will template constraints be available for variabl

2019-07-09 15:50发布

In the latest template constraints paper a new toolset to constrain template arguments is presented. Also, in C++14 variable templates are provided. Variable templates allow the definition of type parameterized constants among other things.

There is no mention of how these feature could interact. Using the canonical example of pi we could have this:

template<Integral T>
  constexpr double pi(3.141592653589793238);

template<Floating_point T>
  constexpr T pi(3.1415926535897932384626433832795029L);

This would enforce the C/C++ numeric conversion from integral to double. It would also prevent instantiation with totally irrelevant types. (Looking at this, we might want to replace Floating_point with something that requires a floating point ctor in order to support complex.)

Did I miss something in one of the papers or is this in the works? Maybe it comes for free and is not worth mentioning?

1条回答
做个烂人
2楼-- · 2019-07-09 16:44

In the latest version of the proposal (N4040, dated May 2014), the answer would be NO:

5 A variable template has the following restrictions:

— The template must be unconstrained.

— The declared type must be bool.

— The declaration must have an initializer.

— The initializer shall be a constraint-expression.

[ Example:

template<typename T>
concept bool D1 = has_x<T>::value; // OK

template<typename T>
concept bool D2 = 3 + 4;           // Error: initializer is not a constraint

template<Integral T>
concept bool D3 = has_x<T>::value; // Error: constrained concept definition

— end example ]

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