Difference between .on('click') vs .click(

2018-12-31 00:18发布

Is there any difference between the following code?

$('#whatever').on('click', function() {
     /* your code here */
});

and

$('#whatever').click(function() {
     /* your code here */
});

标签: jquery click
11条回答
梦寄多情
2楼-- · 2018-12-31 00:57

They appear to be the same... Documentation from the click() function:

This method is a shortcut for .bind('click', handler)

Documentation from the on() function:

As of jQuery 1.7, the .on() method provides all functionality required for attaching event handlers. For help in converting from older jQuery event methods, see .bind(), .delegate(), and .live(). To remove events bound with .on(), see .off().

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爱死公子算了
3楼-- · 2018-12-31 00:57

.click events only work when element gets rendered and are only attached to elements loaded when the DOM is ready.

.on events are dynamically attached to DOM elements, which is helpful when you want to attach an event to DOM elements that are rendered on ajax request or something else (after the DOM is ready).

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旧时光的记忆
4楼-- · 2018-12-31 00:58

As mentioned by the other answers:

$("#whatever").click(function(){ });
// is just a shortcut for
$("#whatever").on("click", function(){ })

Noting though that .on() supports several other parameter combinations that .click() doesn't, allowing it to handle event delegation (superceding .delegate() and .live()).

(And obviously there are other similar shortcut methods for "keyup", "focus", etc.)

The reason I'm posting an extra answer is to mention what happens if you call .click() with no parameters:

$("#whatever").click();
// is a shortcut for
$("#whatever").trigger("click");

Noting that if you use .trigger() directly you can also pass extra parameters or a jQuery event object, which you can't do with .click().

I also wanted to mention that if you look at the jQuery source code (in jquery-1.7.1.js) you'll see that internally the .click() (or .keyup(), etc.) function will actually call .on() or .trigger(). Obviously this means you can be assured that they really do have the same result, but it also means that using .click() has a tiny bit more overhead - not anything to worry or even think about in most circumstances, but theoretically it might matter in extraordinary circumstances.

EDIT: Finally, note that .on() allows you to bind several events to the same function in one line, e.g.:

$("#whatever").on("click keypress focus", function(){});
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闭嘴吧你
5楼-- · 2018-12-31 01:00

Here you will get list of diffrent ways of applying the click event. You can select accordingly as suaitable or if your click is not working just try an alternative out of these.

$('.clickHere').click(function(){ 
     // this is flat click. this event will be attatched 
     //to element if element is available in 
     //dom at the time when JS loaded. 

  // do your stuff
});

$('.clickHere').on('click', function(){ 
    // same as first one

    // do your stuff
})

$(document).on('click', '.clickHere', function(){
          // this is diffrent type 
          //  of click. The click will be registered on document when JS 
          //  loaded and will delegate to the '.clickHere ' element. This is 
          //  called event delegation 
   // do your stuff
});

$('body').on('click', '.clickHere', function(){
   // This is same as 3rd 
   // point. Here we used body instead of document/

   // do your stuff
});

$('.clickHere').off().on('click', function(){ // 
    // deregister event listener if any and register the event again. This 
    // prevents the duplicate event resistration on same element. 
    // do your stuff
})
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明月照影归
6楼-- · 2018-12-31 01:07

They've now deprecated click(), so best to go with on('click')

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浪荡孟婆
7楼-- · 2018-12-31 01:10

As far as ilearned from internet and some friends .on() is used when you dynamically add elements. But when i used it in a simple login page where click event should send AJAX to node.js and at return append new elements it started to call multi-AJAX calls. When i changed it to click() everything went right. Actually i did not faced with this problem before.

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