I have a data.table dat
with 4 columns, say (col1
, col2
, col3
, col4
).
Input data:
structure(list(col1 = c(5.1, 5.1, 4.7, 4.6, 5, 5.1, 5.1, 4.7,
4.6, 5), col2 = c(3.5, 3.5, 3.2, 3.1, 3.6, 3.5, 3.5, 3.2, 3.1,
3.6), col3 = c(1.4, 1.4, 1.3, 1.5, 1.4, 3.4, 3.4, 1.3, 1.5, 1.4
), col4 = structure(c(1L, 1L, 1L, 1L, 1L, 4L, 4L, 4L, 4L, 4L), .Label = c("setosa",
"versicolor", "virginica", "eer"), class = "factor")), .Names = c("col1",
"col2", "col3", "col4"), row.names = c(NA, -10L), class = c("data.table",
"data.frame"))
r
col1 col2 col3 col4
1: 5.1 3.5 1.4 setosa
2: 5.1 3.5 1.4 setosa
3: 4.7 3.2 1.3 setosa
4: 4.6 3.1 1.5 setosa
5: 5.0 3.6 1.4 setosa
6: 5.1 3.5 3.4 eer
7: 5.1 3.5 3.4 eer
8: 4.7 3.2 1.3 eer
9: 4.6 3.1 1.5 eer
10: 5.0 3.6 1.4 eer
I am performing a following operation on col3
for each unique value of col4
dat[ , r_new:= sum(col3, na.rm = T), .(col4)] #syntax 1
So, above sytnax is creating a new column r_new
with values got by adding those values of col3
where col4
is same. So, each unique value of col4
will have a unuique value in column r_new
.
What I want to do now, is do the same as above but not include those rows where col1
and col2
are taking same values (something like below)
dat[col1 is different OR col2 is different , r_new:= sum(col3, na.rm = T), .(col4)]
What this will do, while performing sum
function over rows, it will not include those rows where both col1
and col2
are taking same values.
How can I include this condition in the same syntax as 1?
Expected Output:
col1 col2 col3 col4 r_new
1: 5.1 3.5 1.4 setosa 5.6
2: 5.1 3.5 1.4 setosa 5.6
3: 4.7 3.2 1.3 setosa 5.6
4: 4.6 3.1 1.5 setosa 5.6
5: 5.0 3.6 1.4 setosa 5.6
6: 5.1 3.5 3.4 eer 7.6
7: 5.1 3.5 3.4 eer 7.6
8: 4.7 3.2 1.3 eer 7.6
9: 4.6 3.1 1.5 eer 7.6
10: 5.0 3.6 1.4 eer 7.6
As you can see in the expected output, for setosa
row 1 and 2 took same value for col1
and col2
and for err
rows 6 and 7 took same values for col1
and col2
, so we did not add those rows (we just considered them once). Dont worry about col3
(it will take same value if col1
and col2
are taking same values.
EDIT: Second dput:
structure(list(col1 = c(5.1, 5.1, 4.7, 4.6, 5, 5.1, 5.1, 4.7,
4.6, 5.1), col2 = c(3.5, 3.5, 3.2, 3.1, 3.6, 3.5, 3.5, 3.2, 3.1,
3.4), col3 = c(1.4, 1.4, 1.3, 1.5, 1.4, 3.4, 3.4, 1.3, 1.5, 3.4
), col4 = c("A", "A", "A", "A", "A", "B", "B", "B", "B", "B"),
count = c(1, 1, 1, 1, 1, 1, 1, 1, 1, 1), r_new = c(5.6, 5.6,
5.6, 5.6, 5.6, 9.6, 9.6, 9.6, 9.6, 9.6)), .Names = c("col1",
"col2", "col3", "col4", "count", "r_new"), row.names = c(NA,
-10L), class = c("data.table", "data.frame"))
col1 col2 col3 col4 count r_new
1: 5.1 3.5 1.4 A 1 5.6
2: 5.1 3.5 1.4 A 1 5.6
3: 4.7 3.2 1.3 A 1 5.6
4: 4.6 3.1 1.5 A 1 5.6
5: 5.0 3.6 1.4 A 1 5.6
6: 5.1 3.5 3.4 B 1 9.6
7: 5.1 3.5 3.4 B 1 9.6
8: 4.7 3.2 1.3 B 1 9.6
9: 4.6 3.1 1.5 B 1 9.6
10: 5.1 3.4 3.4 B 1 9.6
EDIT 2: Third dput
col1 col2 col3 col4 count r_new
1: 5.1 3.5 1.4 A 1 5.6
2: 5.1 3.5 1.4 A 1 5.6
3: 4.7 3.2 1.3 A 1 5.6
4: 4.6 3.1 1.5 A 1 5.6
5: 5.0 3.6 1.4 A 1 5.6
6: 5.1 3.5 3.4 B 1 6.2
7: 5.1 3.5 3.4 B 1 6.2
8: 4.7 3.2 1.3 B 1 6.2
9: 4.6 3.1 1.5 B 1 6.2
10: 5.1 3.5 3.4 B 1 6.2
structure(list(col1 = c(5.1, 5.1, 4.7, 4.6, 5, 5.1, 5.1, 4.7,
4.6, 5.1), col2 = c(3.5, 3.5, 3.2, 3.1, 3.6, 3.5, 3.5, 3.2, 3.1,
3.5), col3 = c(1.4, 1.4, 1.3, 1.5, 1.4, 3.4, 3.4, 1.3, 1.5, 3.4
), col4 = c("A", "A", "A", "A", "A", "B", "B", "B", "B", "B"),
count = c(1, 1, 1, 1, 1, 1, 1, 1, 1, 1), r_new = c(5.6, 5.6,
5.6, 5.6, 5.6, 6.2, 6.2, 6.2, 6.2, 6.2)), .Names = c("col1",
"col2", "col3", "col4", "count", "r_new"), row.names = c(NA,
-10L), class = c("data.table", "data.frame"))
We can subset
col3
insidej
using?data.table::duplicated
.Accept mtoto's answer as that's easier to read, but here's an alternative.