OK javascript newbie here, I want help!
Here is the design that explains better the situation.
My Code:
<div class="design">
<div class="menu">5 menu options will be in this div and when we hover at each link an image must appear to the right with fast zoom in effect like shooting.
<li class="menu-item"> <a href="#">menu option</a>
</li>
<li class="menu-item"> <a href="#">menu option</a>
</li>
<li class="menu-item"> <a href="#">menu option</a>
</li>
<li class="menu-item"> <a href="#">menu option</a>
</li>
<li class="menu-item"> <a href="#">menu option</a>
</li>
</div>
<div class="zoom-preview">image will appear here when we hover at each link at the left. each link it's own image. Also there must be a default image here when we do not hover at any link at the left.</div>
<div class="clear"></div>
All I want to do is when we enter the page there will be a default image at right. But when we hover at each link at the left, the image on the right will be replaced with another image, with a fast zoom effect like shooting for example.
When no link is hovered the default image will be again displayed.
Please some help with the javascript code.. Thanks!
JSFiddle: http://jsfiddle.net/r6ywtk6u/
You will need to put a source for the images
Jquery:
HTML:
on hover enter, you take the html inside the link and put it in the display box. when it leaves, you put the original content back.
Here is a quick demo that will get you started:
Demo:jsFiddle
As you can see I'm using a list with data attributes to set which image should be displayed (
<li data-image='image.jpg'><a ...></a></li>
) - the rest is handled by JS.To control the behavior change the variables value as needed: