So I input strings into an array mydata[10][81]
while ((ct<=10) && gets(mydata[ct]) != NULL && (mydata[ct++][0] != '\0'))
I then use a for loop to create a second array of pointers
for (i=0;i<11;i++){
ptstr[i] = mydata[i];
}
This is where I get stuck
I know I need to use strlen
somehow, but I can't even conceive of how to get the length of a pointer and then re-assign that pointer a new position based on a third additional value of length
Hopefully that makes sense, I'm so lost on how to do it or explain it, I'm just trying to sort strings by length using array positions (not using something like qsort
)
I did some more work on it and came up with this: any idea why its not working?
void orderLength(char *ptstr[], int num){
int temp;
char *tempptr;
int lengthArray[10];
int length = num;
int step, i, j, u;
for (i=0; i<num;i++){
lengthArray[i] = strlen(ptstr[i]);
}
for (step=0; step < length; step++){
for(j = step+1; j < step; j++){
if (lengthArray[j] < lengthArray[step]){
temp = lengthArray[j];
lengthArray[j] = lengthArray[step];
lengthArray[step] =temp;
tempptr=ptstr[j];
ptstr[j]=ptstr[step];
}
}
}
for (u=0; u<num; u++){
printf("%s \n", ptstr[u]);
}
}
To avoid to call several time strlen() on the same strings, you can use a listed chain of structures like following :
A really simple version might look like this. It's a bubble sort which is pretty slow for any reasonable size data but it looks like you're only sorting 11 elements so it won't matter here.
The key is the 'if' statement which compares the lengths of the two array positions. The next three lines swap them if they were out of order.
Edit: If you want to sort by the contents of the string not the length then change the if statement to:
(note: you're better off using strncmp where possible)
As suggested in the comments by Deduplicator, use
qsort
defined instdlib.h
.