Display MySQL results by date

Question

I have this mysql Table:

+--------------------+---------+-------+
|      date          | query   | count |
|--------------------+---------+-------|
|2012-11-18 09:52:00 | Michael |   1   |
|2012-11-18 10:47:10 |  Tom    |   2   |
|2012-11-17 15:02:12 |  John   |   1   |
|2012-11-17 22:52:10 |  Erik   |   3   |
|2012-11-16 09:42:01 |  Larry  |   1   |
|2012-11-16 07:41:33 |  Kate   |   1   |
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

and so on. I can simply take results and order them by date in one row via this code:

$queries = mysql_query("SELECT * FROM my_tables ORDER BY date DESC LIMIT 20"); 
while($row = mysql_fetch_array($queries)){
    echo "Name ".$row['query']."";
}

But how to display elements from table ordered by specific date like this:

In 2012-11-18:
Michael
Tom

In 2012-11-17:
John
Erik

In 2012-11-16:
Larry
Kate

and so on. Thanks!

Answer 1

Use this:

SELECT * FROM my_tables WHERE date > "2012-11-16" ORDER BY date LIMIT 4

Answer 2

+1 good question, THIS QUESTION IS NOT SIMPLY HOW TO ORDER A QUERY!!

I think this can be done using GROUP_CONCAT function. this will combine the matching results when you group them and seperate them by commas. ONce you have the results you can explode or do whatever you want

http://www.w3resource.com/mysql/aggregate-functions-and-grouping/aggregate-functions-and-grouping-group_concat.php

Your going to have to convert and group by date, and group_concat the names. then (in php or whathaveyou) explode the names by commas, and echo the date followed by the names for each result.

edit Looks like you wanted a PHP way to solve this? oops

Answer 3

Try the WHERE statement:

   select * from my_table where date_column > "2012-11-18 00:00:00" and date_column < "2012-11-18 23:59:59" order by date_column

Answer 4

Here is teh PHP code:

$query = mysql_query("SELECT date, query FROM table6 ORDER BY date DESC LIMIT 20");
$group_date = null;
while ($row = mysql_fetch_assoc($query)) {
    if ($group_date !== substr($row["date"], 0, 10)) {
        $group_date = substr($row["date"], 0, 10);
        echo "<h1>$group_date</h1>\n";
    }
    echo "${row['query']}<br>\n";
}

Output:

2012-11-18

Tom

Michael

2012-11-17

Erik

John

2012-11-16

Larry

Kate

Note that while this code "groups" rows by one column, it can easily be extended to group rows by multiple columns. Left as an exercise.

Answer 5

What about

 SELECT * FROM my_tables GROUP BY YEAR(date), MONTH(date), DAY(date) ORDER BY date DESC LIMIT 20