sqrt() function not working with variable argument

2019-01-09 13:14发布

I don't know if I'm missing something obvious, but it appears that I'm unable to compute square roots of a variable in C; the sqrt() function only seems to work on constants. This is my code:

#include <math.h>
#include <stdio.h>

int main()
{
    double a = 2.0;
    double b = sqrt(a);
    printf("%f", b);
    return 0;
}

When I run this program, I get the following error:

gcc -Wall -o "test2" "test2.c" (in directory: /home/eddy/Code/euler)
/tmp/ccVfxkNh.o: In function `main':
test2.c:(.text+0x30): undefined reference to `sqrt'
collect2: ld returned 1 exit status
Compilation failed.

However, if I replace the argument in sqrt() with a constant such as 2.0 for example, (b = sqrt(2.0)), then it works fine. Is sqrt() not supposed to work with variables or something?

Thanks for the help

8条回答
相关推荐>>
2楼-- · 2019-01-09 13:32

include math library using " " operator

#include " math.h "

compile program using -lm option for inherit math library suppose our program name is test.c the we compile as follow

gcc test.c -lm
查看更多
Rolldiameter
3楼-- · 2019-01-09 13:37

This works fine for me. I think there is some problem with ur math library. Try linking it again and see. Other wise code is completely perfect.

查看更多
神经病院院长
4楼-- · 2019-01-09 13:38

Use the command gcc -Wall -o "test2" "test2.c" -lm which will likely fix this.

This includes the math library in addition to the standard C runtime library. On most systems, the math library is historically a separate entity that needs to be explicitly requested.

查看更多
贪生不怕死
5楼-- · 2019-01-09 13:45

Compile with:

gcc -Wall -o test2 test2.c -lm

You need to link against the math library.

查看更多
混吃等死
6楼-- · 2019-01-09 13:45

gcc does not link the standard libraries by default. So you just need to do this if compiling via gcc:

gcc filename.c -lm .

However in case of g++ no need to link the library so this will work fine :

g++ filename.c -o filename

查看更多
劳资没心,怎么记你
7楼-- · 2019-01-09 13:47

You need to link with the math library (use a '-lm' on the command line). In the constant case, the compiler is probably being smart and precomputing sqrt(2.0) (so the code that is compiled is essentially 'b = 1.414...;')

查看更多
登录 后发表回答