{var%20f='http://v.t.sina.com.cn/share/share.php?appkey=1515056452',u=z||d.location,p=['&url=',e(u),'&title=',e(t||d.title),'&source=',e(r),'&sourceUrl=',e(l),'&content=',c||'gb2312','&pic=',e(p||'')].join('');function%20a(){if(!window.open([f,p].join(''),'mb',['toolbar=0,status=0,resizable=1,width=440,height=430,left=',(s.width-440)/2,',top=',(s.height-430)/2].join('')))u.href=[f,p].join('');};if(/Firefox/.test(navigator.userAgent))setTimeout(a,0);else%20a();})(screen,document,encodeURIComponent,'','','https://www.manongdao.com/data/attach/logo/logo.png', '推荐 Root（大扎） 的问题《xsl sum siblings based on node value》','https://www.manongdao.com/q-794972.html','页面编码gb2312|utf-8默认gb2312'));){kind=link}
I need to apply an xsl transformation that sums certain node values based on the value of one of its sibling nodes. Here's my xml pseudo code:
<?xml version="1.0" encoding="ISO-8859-1" ?>
<Message>
<Body>
<Order>
<Item>
<.../>
<Type>widget</Type>
<Qty>20</Qty>
<.../>
</Item>
<Item>
<.../>
<Type>gadget</Type>
<Qty>10</Qty>
<.../>
</Item>
<Item>
<.../>
<Type>widget</Type>
<Qty>5</Qty>
<.../>
</Item>
<Item/>
</Order>
</Body>
</Message>
The desired result of the the quantity summation for all items of type 'widget' is 25
<xsl:value-of select="sum(/Message/Body/Order/Item/Qty)"/>
is yielding 35
My xsl stylesheet details
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fn="http://www.w3.org/2005/xpath-functions"
version="2.0"
Try to add predicates to find the nodes that you're interested (i.e. 'widget') only: