How do you get a list of the names of all files pr

2018-12-31 16:51发布

I'm trying to get a list of the names of all the files present in a directory using Node.js. I want output that is an array of filenames. How can I do this?

16条回答
若你有天会懂
2楼-- · 2018-12-31 17:49

Using Promises with ES7

Asynchronous use with mz/fs

The mz module provides promisified versions of the core node library. Using them is simple. First install the library...

npm install mz

Then...

const fs = require('mz/fs');
fs.readdir('./myDir').then(listing => console.log(listing))
  .catch(err => console.error(err));

Alternatively you can write them in asynchronous functions in ES7:

async function myReaddir () {
  try {
    const file = await fs.readdir('./myDir/');
  }
  catch (err) { console.error( err ) }
};

Update for recursive listing

Some of the users have specified a desire to see a recursive listing (though not in the question)... Use fs-promise. It's a thin wrapper around mz.

npm install fs-promise;

then...

const fs = require('fs-promise');
fs.walk('./myDir').then(
    listing => listing.forEach(file => console.log(file.path))
).catch(err => console.error(err));
查看更多
十年一品温如言
3楼-- · 2018-12-31 17:50

Here's an asynchronous recursive version.

    function ( path, callback){
     // the callback gets ( err, files) where files is an array of file names
     if( typeof callback !== 'function' ) return
     var
      result = []
      , files = [ path.replace( /\/\s*$/, '' ) ]
     function traverseFiles (){
      if( files.length ) {
       var name = files.shift()
       fs.stat(name, function( err, stats){
        if( err ){
         if( err.errno == 34 ) traverseFiles()
    // in case there's broken symbolic links or a bad path
    // skip file instead of sending error
         else callback(err)
        }
        else if ( stats.isDirectory() ) fs.readdir( name, function( err, files2 ){
         if( err ) callback(err)
         else {
          files = files2
           .map( function( file ){ return name + '/' + file } )
           .concat( files )
          traverseFiles()
         }
        })
        else{
         result.push(name)
         traverseFiles()
        }
       })
      }
      else callback( null, result )
     }
     traverseFiles()
    }
查看更多
素衣白纱
4楼-- · 2018-12-31 17:51

The answer above does not perform a recursive search into the directory though. Here's what I did for a recursive search (using node-walk: npm install walk)

var walk    = require('walk');
var files   = [];

// Walker options
var walker  = walk.walk('./test', { followLinks: false });

walker.on('file', function(root, stat, next) {
    // Add this file to the list of files
    files.push(root + '/' + stat.name);
    next();
});

walker.on('end', function() {
    console.log(files);
});
查看更多
泪湿衣
5楼-- · 2018-12-31 17:51

Get files in all subdirs

function getFiles (dir, files_){
    files_ = files_ || [];
    var files = fs.readdirSync(dir);
    for (var i in files){
        var name = dir + '/' + files[i];
        if (fs.statSync(name).isDirectory()){
            getFiles(name, files_);
        } else {
            files_.push(name);
        }
    }
    return files_;
}

console.log(getFiles('path/to/dir'))
查看更多
登录 后发表回答