How do you get a list of the names of all files pr

2018-12-31 16:51发布

I'm trying to get a list of the names of all the files present in a directory using Node.js. I want output that is an array of filenames. How can I do this?

16条回答
宁负流年不负卿
2楼-- · 2018-12-31 17:29

Load fs:

const fs = require('fs');

Read files async:

fs.readdir('./dir', function (err, files) {
    // "files" is an Array with files names
});

Read files sync:

var files = fs.readdirSync('./dir');
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裙下三千臣
3楼-- · 2018-12-31 17:29
function getFilesRecursiveSync(dir, fileList, optionalFilterFunction) {
    if (!fileList) {
        grunt.log.error("Variable 'fileList' is undefined or NULL.");
        return;
    }
    var files = fs.readdirSync(dir);
    for (var i in files) {
        if (!files.hasOwnProperty(i)) continue;
        var name = dir + '/' + files[i];
        if (fs.statSync(name).isDirectory()) {
            getFilesRecursiveSync(name, fileList, optionalFilterFunction);
        } else {
            if (optionalFilterFunction && optionalFilterFunction(name) !== true)
                continue;
            fileList.push(name);
        }
    }
}
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残风、尘缘若梦
4楼-- · 2018-12-31 17:31

Dependencies.

var fs = require('fs');
var path = require('path');

Definition.

// String -> [String]
function fileList(dir) {
  return fs.readdirSync(dir).reduce(function(list, file) {
    var name = path.join(dir, file);
    var isDir = fs.statSync(name).isDirectory();
    return list.concat(isDir ? fileList(name) : [name]);
  }, []);
}

Usage.

var DIR = '/usr/local/bin';

// 1. List all files in DIR
fileList(DIR);
// => ['/usr/local/bin/babel', '/usr/local/bin/bower', ...]

// 2. List all file names in DIR
fileList(DIR).map((file) => file.split(path.sep).slice(-1)[0]);
// => ['babel', 'bower', ...]

Please note that fileList is way too optimistic. For anything serious, add some error handling.

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只靠听说
5楼-- · 2018-12-31 17:31

I made a node module to automate this task: mddir

Usage

node mddir "../relative/path/"

To install: npm install mddir -g

To generate markdown for current directory: mddir

To generate for any absolute path: mddir /absolute/path

To generate for a relative path: mddir ~/Documents/whatever.

The md file gets generated in your working directory.

Currently ignores node_modules, and .git folders.

Troubleshooting

If you receive the error 'node\r: No such file or directory', the issue is that your operating system uses different line endings and mddir can't parse them without you explicitly setting the line ending style to Unix. This usually affects Windows, but also some versions of Linux. Setting line endings to Unix style has to be performed within the mddir npm global bin folder.

Line endings fix

Get npm bin folder path with:

npm config get prefix

Cd into that folder

brew install dos2unix

dos2unix lib/node_modules/mddir/src/mddir.js

This converts line endings to Unix instead of Dos

Then run as normal with: node mddir "../relative/path/".

Example generated markdown file structure 'directoryList.md'

    |-- .bowerrc
    |-- .jshintrc
    |-- .jshintrc2
    |-- Gruntfile.js
    |-- README.md
    |-- bower.json
    |-- karma.conf.js
    |-- package.json
    |-- app
        |-- app.js
        |-- db.js
        |-- directoryList.md
        |-- index.html
        |-- mddir.js
        |-- routing.js
        |-- server.js
        |-- _api
            |-- api.groups.js
            |-- api.posts.js
            |-- api.users.js
            |-- api.widgets.js
        |-- _components
            |-- directives
                |-- directives.module.js
                |-- vendor
                    |-- directive.draganddrop.js
            |-- helpers
                |-- helpers.module.js
                |-- proprietary
                    |-- factory.actionDispatcher.js
            |-- services
                |-- services.cardTemplates.js
                |-- services.cards.js
                |-- services.groups.js
                |-- services.posts.js
                |-- services.users.js
                |-- services.widgets.js
        |-- _mocks
            |-- mocks.groups.js
            |-- mocks.posts.js
            |-- mocks.users.js
            |-- mocks.widgets.js
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与风俱净
6楼-- · 2018-12-31 17:36

You don't say you want to do it recursively so I assume you only need direct children of the directory.

Sample code:

const fs = require('fs');
const path = require('path');

fs.readdirSync('your-directory-path')
  .filter((file) => fs.lstatSync(path.join(folder, file)).isFile());
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柔情千种
7楼-- · 2018-12-31 17:42

Took the general approach of @Hunan-Rostomyan, made it a litle more concise and added excludeDirs argument. It'd be trivial to extend with includeDirs, just follow same pattern:

import * as fs from 'fs';
import * as path from 'path';

function fileList(dir, excludeDirs?) {
    return fs.readdirSync(dir).reduce(function (list, file) {
        const name = path.join(dir, file);
        if (fs.statSync(name).isDirectory()) {
            if (excludeDirs && excludeDirs.length) {
                excludeDirs = excludeDirs.map(d => path.normalize(d));
                const idx = name.indexOf(path.sep);
                const directory = name.slice(0, idx === -1 ? name.length : idx);
                if (excludeDirs.indexOf(directory) !== -1)
                    return list;
            }
            return list.concat(fileList(name, excludeDirs));
        }
        return list.concat([name]);
    }, []);
}

Example usage:

console.log(fileList('.', ['node_modules', 'typings', 'bower_components']));
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