I've seen a number of example scripts online that use this. Most recently, I saw it in a script on automating TFS:
[string] $fields = "Title=$($taskTitle);Description=$($taskTitle);Assigned To=$($assignee);"
$fields += "Area Path=$($areaPath);Iteration Path=$($iterationPath);Discipline=$($taskDisciplineArray[$i]);Priority=$($i+1);"
$fields += "Estimate=$($taskEstimateArray[$i]);Remaining Work=$($taskRemainingArray[$i]);Completed Work=$($tasktaskCompletedArray[$i])"
From what I can tell, $($taskTitle)
seems to be equivalent to $taskTitle
. Am I missing something? Is there any reason to use the parentheses and extra dollar sign?
The syntax helps with evaluating the expression inside it.
You can read more at http://ss64.com/ps/syntax-operators.html
To complement Amith George's helpful answer with more background information:
Indeed, in the context of
"..."
, an expandable string (interpolating string):You do NOT need
$(...)
with a simple variable reference such as$taskTitle
or$env:HOME
${taskTitle}
or${env:HOME}
- i.e.,{...}
around the identifier - so as to disambiguate the variable name from subsequent characters in the string.You DO need
$(...)
for anything else:"count is: $($var.Count)"
"path prefix: $($var + '/')"
"file names: $(Get-ChildItem *.txt | Select-Object -ExpandProperty Name)"
In short:
$(...)
inside "...
" is needed for anything other than simple variable references and allows you to embed entire statements inside"..."
; as usual, when the string is evaluated, the$(...)
part is replaced with the (stringified) output from the embedded statement(s).If you don't want to think about when
$(...)
is and isn't needed, you can choose to always use it (e.g.,$($taskTitle)
), but note that it's cumbersome to type and visually "noisy".$($var)
is not the same as that of$var
/${var}
, namely if$var
is a collection (implementing[System.Collections.IEnumerable]
) that happens to contain only a single item - see PetSerAl's comments below.Unless the referenced variable's / embedded statement's value already is a string, it is stringified using the .NET
.ToString()
method, with the notable twist that types that support culture-sensitive stringification are stringified with the invariant culture, which, loosely speaking, is like US-English format; e.g.,"$(1.2)"
always yields1.2
, even in cultures where,
is the decimal mark; see this answer of mine for more.Documentation:
The official name for
$(...)
is the subexpression operator, as (tersely) documented inGet-Help about_Operators
, though the explanation there doesn't discuss the operator's specific use in the context of expandable strings.Conversely,
Get-Help about_Quoting_Rules
, which discusses string literals including expandable strings, shows examples of$(...)
use only in the context of expandable strings.