How to pass parameter in multipart post request

Servlet code

request.getparameter("fname") //I can't able to get value.

HTML code

 <html>
    <head>
    <title>File Uploading Form</title>
    </head>
    <body>
    <h3>File Upload:</h3>
    Select a file to upload: <br />
    <form action="UploadServlet" method="post"
                            enctype="multipart/form-data">
    <input type="text" name="fname" size="50" />   
 <input type="file" name="file" size="50" />
 <input type="submit" value="Upload File" />
    </form>
    </body>
    </html>

My question is : How to pass fname parameter in multipart post request?

标签： jsp servlets file-upload multipartform-data

2条回答

Deceive 欺骗

2楼-- · 2019-06-21 21:47

Link Each Programms
------------------------------------------------------

import java.sql.*;
import java.io.*;

import javax.servlet.ServletException;
import javax.servlet.annotation.MultipartConfig;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.Part;
import javax.servlet.annotation.MultipartConfig;
import javax.servlet.annotation.WebServlet;
import java.util.Hashtable;
import java.util.List;

import org.apache.commons.fileupload.FileItem;
import org.apache.commons.fileupload.ParameterParser;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.servlet.ServletFileUpload;


/**
 * Servlet implementation class Recent
 */
@WebServlet("/Recent")
@MultipartConfig
public class Recent extends HttpServlet {
    private static final long serialVersionUID = 1L;

    /**
     * @see HttpServlet#HttpServlet()
     */
    public Recent() {
        super();
        // TODO Auto-generated constructor stub
    }

    /**
     * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
     */
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

        // TODO Auto-generated method stub
         Sample  s1=new Sample();
         final String UPLOAD_DIRECTORY = "/home/pradeep/Documents/pradeep/WebContent/Images";
         if(ServletFileUpload.isMultipartContent(request)){
                try {
         List<FileItem> multiparts = new 
                            ServletFileUpload(new DiskFileItemFactory()).parseRequest(request);

                    for(FileItem item : multiparts){
                        if(!item.isFormField())
                        {
                            String name = new File(item.getName()).getName();
                            item.write( new File(UPLOAD_DIRECTORY + File.separator + name));
                            String Path= "/home/pradeep/Documents/pradeep/WebContent/Images/" +name;


                          s1.connecting(Path);


                        }
                    }

                        request.setAttribute("message", "File Uploaded Successfully");
                } catch (Exception ex) {
                   request.setAttribute("message", "File Upload Failed due to " + ex);
                }          

            }else{
                request.setAttribute("message",
                                     "Sorry this Servlet only handles file upload request");
            }



                request.getRequestDispatcher("/Result.jsp").forward(request, response);




    }

}
-------------------------------------------------------------------------------------------
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;

import dbconnections.Connections;



public class Sample {
    Connections con=new Connections();

    public void connecting(String Path)
    {
        Connection conn=con.Connect();

        PreparedStatement pst;
        String query="INSERT INTO Student1 (Path) values (?)";
       try {

            pst=conn.prepareStatement(query);
            pst.setString(1,Path);
            pst.executeUpdate();

        } catch (SQLException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        // TODO Auto-generated method stub
    }


}
-------------------------------------------------------------------------------------
<%@ page language="java" contentType="text/html; charset=UTF-8"
    pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
</head>
<body>
<div>
            <h3> Choose File to Upload in Server </h3>          
           <form action="Recent" method="post" enctype="multipart/form-data">

            <input type="file" name="file" />
            <input type="submit" value="upload" />
            </form>          
        </div>


</body>
</html>

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劫难

3楼-- · 2019-06-21 21:50

Short answer: you will find the fname in the Parts of the request.

Long answer: For multipart type requests, even the simple <input type="text"> field values are placed in parts. You will have to iterate over the Part objects returned by HttpServletRequest.getParts() and handle them according to their name property:

for( Part p : request.getParts() ) {
    if( "fname".equals(p.getName()) ) {
        ...
    }
    else if( "file".equals(p.getName()) ) {
        ...
    }
}

To complicate things further, the content of the part is available as InputStream - Part.getInputStream() - so you will have to do a little transforming stream → byte[] → String to get the value.

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