I have the worlds most simple javascript function:
fnSubmit()
{
window.print();
document.formname.submit();
}
Which is called by:
<button type="button" id="submit" onclick="fnSubmit()">Submit</button>
All is well and good, the print dialog shows up, however after printing or canceling the print I get the following error:
"document.formname.submit is not a function"
My form is defined as follows: (obviously I am not using formname in the actual code but you get the idea)
<form name="formname" id="formname" method="post" action="<?=$_SERVER['SCRIPT_NAME']?>">
Obviously I am not trying to do anything special here and I have used similar approaches in the past, what in the world am I missing here?
The most likely culprit is IE confusing JavaScript variables, ids, and names. Search in your source for something sharing the name of your form.
Given that your form has both an
id
and aname
defined, you could use either one of these:With the
form
tag'sid
:With the
form
tag'sname
attribute:Try this:
In short: change the id of your submit button to something different than "submit". Also, don't set the name to this value either.
Now, some deeper insight. The general case is that
document.formname.submit
is a method that, when called, will submit the form. However, in your example,document.formname.submit
is not a method anymore, but the DOM node representing the button.This happens because elements of a form are available as attributes of its DOM node, via their
name
andid
attributes. This wording is a bit confusing, so here comes an example:On this example,
document.forms.example.exampleField
is a DOM node representing the field with name "exampleField". You can use JS to access its properties such as its value:document.forms.example.exampleField.value
.However, on this example there is an element of the form called "submit", and this is the submit button, which can be accessed with
document.forms.example.submit
. This overwrites the previous value, which was the function that allows you to submit the form.EDIT:
If renaming the field isn't good for you, there is another solution. Shortly before writing this, I left the question on the site and got a response in the form of a neat JavaScript hack:
See How to reliably submit an HTML form with JavaScript? for complete details
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