Looking for an answer for C# and C++. (in C#, replace 'destructor' with 'finalizer')
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If the constructor doesn't finish executing, the object doesn't exist, so there's nothing to destruct. This is in C++, I have no idea about C#.
It does for C# (see code below) but not for C++.
This prints "Finalized"
Preamble: Herb Sutter has a great article on the subject:
http://herbsutter.wordpress.com/2008/07/25/constructor-exceptions-in-c-c-and-java/
C++ : Yes and No
While an object destructor won't be called if its constructor throws (the object "never existed"), the destructors of its internal objects could be called.
As a summary, every internal parts of the object (i.e. member objects) will have their destructors called in the reverse order of their construction. Every thing built inside the constructor won't have its destructor called unless RAII is used in some way.
For example:
The order of creation will be:
Let's say we are using the following code:
Some possible cases:
Should m_aData throw at construction, m_aObject will have its destructor called. Then, the memory allocated by "new Class" is deallocated.
Should m_pThing throw at new Thing (out of memory), m_aData, and then m_aObject will have their destructors called. Then, the memory allocated by new Class is deallocated.
Should m_pThing throw at construction, the memory allocated by "new Thing" will be deallocated. Then m_aData, and then m_aObject will have their destructors called. Then, the memory allocated by new Class is deallocated.
Should m_pGizmo throw at construction, the memory allocated by "new Gizmo" will be deallocated. Then m_aData, and then m_aObject will have their destructors called. Then, the memory allocated by new Class is deallocated. Note that m_pThing leaked
If you want to offer the Basic Exception Guarantee, you must not leak, even in the constructor. Thus, you'll have to write this this way (using STL, or even Boost):
Or even:
if you want/need to create those objects inside the constructor.
This way, no matter where the constructor throws, nothing will be leaked.
C++ -
Nope. Destructor is not called for partially constructed objects. A Caveat: The destructor will be called for its member objects which are completely constructed. (Includes automatic objects, and native types)
BTW - What you're really looking for is called "Stack Unwinding"
Don't do things that cause exceptions in the constructor.
Call an Initialize() after the constructor that can throw exceptions.
In C++, the answer is no - object's destructor is not called.
However, the destructors of any member data on the object will be called, unless the exception was thrown while constructing one of them.
Member data in C++ is initialized (i.e. constructed) in the same order as it is declared, so when the constructor throws, all member data that has been initialized - either explicitly in the Member Initialization List (MIL) or otherwise - will be torn down again in reverse order.