Python code for the coin toss issues

Question

I've been writing a program in python that simulates 100 coin tosses and gives the total number of tosses. The problem is that I also want to print the total number of heads and tails.

Here's my code:

import random
tries = 0
while tries < 100:
    tries += 1
    coin = random.randint(1, 2)
    if coin == 1:
        print('Heads')
    if coin == 2:
        print ('Tails')
total = tries
print(total)

I've been racking my brain for a solution and so far I have nothing. Is there any way to get the number of heads and tails printed in addition to the total number of tosses?

Answer 1

Keep a running track of the number of heads:

import random
tries = 0
heads = 0
while tries < 100:
    tries += 1
    coin = random.randint(1, 2)
    if coin == 1:
        heads += 1
        print('Heads')
    if coin == 2:
        print ('Tails')
total = tries
print('Total heads '.format(heads))
print('Total tails '.format(tries - heads))
print(total)

Answer 2

import random

total_heads = 0
total_tails = 0
count = 0


while count < 100:

    coin = random.randint(1, 2)

    if coin == 1:
        print("Heads!\n")
        total_heads += 1
        count += 1

    elif coin == 2:
        print("Tails!\n")
        total_tails += 1
        count += 1

print("\nOkay, you flipped heads", total_heads, "times ")
print("\nand you flipped tails", total_tails, "times ")

Answer 3

# Please make sure to import random.

import random

# Create a list to store the results of the for loop; number of tosses are limited by range() and the returned values are limited by random.choice().

tossed = [random.choice(["heads", "tails"]) for toss in range(100)]

# Use .count() and .format() to calculate and substitutes the values in your output string.

print("There are {} heads and {} tails.".format(tossed.count("heads"), tossed.count("tails")))

Answer 4

You could use random.getrandbits() to generate all 100 random bits at once:

import random

N = 100
# get N random bits; convert them to binary string; pad with zeros if necessary
bits = "{1:>0{0}}".format(N, bin(random.getrandbits(N))[2:])
# print results
print('{total} {heads} {tails}'.format(
    total=len(bits), heads=bits.count('0'), tails=bits.count('1')))

Output

100 45 55

Answer 5

import random
tries = 0
heads=0
tails=0
while tries < 100:
    tries += 1
    coin = random.randint(1, 2)
    if coin == 1:
        print('Heads')
        heads+=1
    if coin == 2:
        print ('Tails')
        tails+=1
total = tries
print(total)
print tails
print heads

Answer 6

You have a variable for the number of tries, which allows you to print that at the end, so just use the same approach for the number of heads and tails. Create a heads and tails variable outside the loop, increment inside the relevant if coin == X block, then print the results at the end.