Subtract matrix of n,k dimensions from array of ma

2019-06-18 04:47发布

If I have an array A

A <- array(0, c(4, 3, 5))
for(i in 1:5) {
  set.seed(i)
  A[, , i] <- matrix(rnorm(12), 4, 3)
}

and if I have matrix B

set.seed(6)
B <- matrix(rnorm(12), 4, 3)

The code to subtract B from the each matrix of the array A would be:

d<-array(0, c(4,3,5))
for(i in 1:5){
  d[,,i]<-A[,,i]-B
}

However, what would be the code to perform the same calculation using a function from "apply" family?

3条回答
欢心
2楼-- · 2019-06-18 05:13

This is what sweep is for.

sweep(A, 1:2, B)
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家丑人穷心不美
3楼-- · 2019-06-18 05:18

Maybe not very intuitive:

A[] <- apply(A, 3, `-`, B)
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Rolldiameter
4楼-- · 2019-06-18 05:36

Because you are looping on the last array dimension, you can simply do:

d <- A - as.vector(B)

and it will be much faster. It is the same idea as when you subtract a vector from a matrix: the vector is recycled so it is subtracted to each column.

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