I have tried several SMT solvers (CVC3, CVC4 and Z3) on the following seemingly trivial benchmark:
(set-logic LIA)
(set-info :smt-lib-version 2.0)
(assert (forall (( x Int)) (forall ((y Int)) (= y x))))
(check-sat)
(exit)
The solvers all return unknown. I understand that this is an undecidable fragment (well non-linear) but I was expecting there would be some simple instantiation heuristics that could solve it. I also tried adding some extra assertions with constants but it didn't help.
Is there a way to attack these problems and what are the limits of reasoning in quantified arithmetic in SMT?
Pad is correct, the
qe
preprocessor can be quite expensive. Moreover, it is not effective in formulas coming from software verification tools such as VCC, Poirot, Dafny, VeriFast, Why3, and ESCJava2. It is not effective because the formulas produced by these applications also contain uninterpreted functions, arrays, etc.As Pad's answer suggests, Z3 is a collection of engines. It provides APIs and commands that allow users to select which engine (or combination of engines) will be used to solve a problem. When the user just says
(check-sat)
is tries to guess what is the best engine for solving the input formula. The guess is based on the structure of input formula and annotations provided by the user (example: theset-logic
command). We are continuously expanding the set of fragments that are automatically detected, and the set of engines we provide.That being said, it is embarrassing that Z3 missed a fragment such as
LIA
and did not automatically applied theqe
procedure to it. ForLIA
formulas,qe
is usually the best option. Alternatives based on E-matching or MBQI are not effective since they are meant for completely different fragments.I just committed code that detects
LIA
(even whenset-logic
is not used). The change is already available in theunstable
(working-in-progress) branch. It will be available tomorrow in the nightly builds, and in the next official release.Your example falls into Linear Integer Arithmetic (LIA) category.
LIA i.e. Presburger Arithmetic admits quantifier elimination (qe) though time complexity of qe procedures is prohibitively high.
I'm not sure that CVC3 and CVC4 support quantifier elimination for LIA, but in Z3 you can do
From Rise4Fun execution, I've got
unsat
result.Here the
qe
tactic is a preprocessing step before applying end-game tacticsmt
.