Resizing an Image without losing any quality [clos

Question

I need to resize an image, but the image quality cannot be affected by this.

Answer 1

private static Image resizeImage(Image imgToResize, Size size)
{
    int sourceWidth = imgToResize.Width;
    int sourceHeight = imgToResize.Height;

    float nPercent = 0;
    float nPercentW = 0;
    float nPercentH = 0;

    nPercentW = ((float)size.Width / (float)sourceWidth);
    nPercentH = ((float)size.Height / (float)sourceHeight);

    if (nPercentH < nPercentW)
        nPercent = nPercentH;
    else
        nPercent = nPercentW;

    int destWidth = (int)(sourceWidth * nPercent);
    int destHeight = (int)(sourceHeight * nPercent);

    Bitmap b = new Bitmap(destWidth, destHeight);
    Graphics g = Graphics.FromImage((Image)b);
    g.InterpolationMode = InterpolationMode.HighQualityBicubic;

    g.DrawImage(imgToResize, 0, 0, destWidth, destHeight);
    g.Dispose();

    return (Image)b;
}

from here

Answer 2

Are you resizing larger, or smaller? By a small % or by a larger factor like 2x, 3x? What do you mean by quality for your application? And what type of images - photographs, hard-edged line drawings, or what? Writing your own low-level pixel grinding code or trying to do it as much as possible with existing libraries (.net or whatever)?

There is a large body of knowledge on this topic. The key concept is interpolation.

Browsing recommendations:
* http://www.all-in-one.ee/~dersch/interpolator/interpolator.html
* http://www.cambridgeincolour.com/tutorials/image-interpolation.htm
* for C#: https://secure.codeproject.com/KB/GDI-plus/imageprocessing4.aspx?display=PrintAll&fid=3657&df=90&mpp=25&noise=3&sort=Position&view=Quick&fr=26&select=629945 * this is java-specific but might be educational - http://today.java.net/pub/a/today/2007/04/03/perils-of-image-getscaledinstance.html

Answer 3

As rcar says, you can't without losing some quality, the best you can do in c# is:

Bitmap newImage = new Bitmap(newWidth, newHeight);
using (Graphics gr = Graphics.FromImage(newImage))
{
    gr.SmoothingMode = SmoothingMode.HighQuality;
    gr.InterpolationMode = InterpolationMode.HighQualityBicubic;
    gr.PixelOffsetMode = PixelOffsetMode.HighQuality;
    gr.DrawImage(srcImage, new Rectangle(0, 0, newWidth, newHeight));
}

Answer 4

There is something out there, context aware resizing, don't know if you will be able to use it, but it's worth looking at, that's for sure

A nice video demo (Enlarging appears towards the middle) http://www.youtube.com/watch?v=vIFCV2spKtg

Here there could be some code. http://www.semanticmetadata.net/2007/08/30/content-aware-image-resizing-gpl-implementation/

Was that overkill? Maybe there are some easy filters you can apply to an enlarged image to blur the pixels a bit, you could look into that.

Answer 5

Here you can find also add watermark codes in this class :

public class ImageProcessor
    {
        public Bitmap Resize(Bitmap image, int newWidth, int newHeight, string message)
        {
            try
            {
                Bitmap newImage = new Bitmap(newWidth, Calculations(image.Width, image.Height, newWidth));

                using (Graphics gr = Graphics.FromImage(newImage))
                {
                    gr.SmoothingMode = SmoothingMode.AntiAlias;
                    gr.InterpolationMode = InterpolationMode.HighQualityBicubic;
                    gr.PixelOffsetMode = PixelOffsetMode.HighQuality;
                    gr.DrawImage(image, new Rectangle(0, 0, newImage.Width, newImage.Height));

                    var myBrush = new SolidBrush(Color.FromArgb(70, 205, 205, 205));

                    double diagonal = Math.Sqrt(newImage.Width * newImage.Width + newImage.Height * newImage.Height);

                    Rectangle containerBox = new Rectangle();

                    containerBox.X = (int)(diagonal / 10);
                    float messageLength = (float)(diagonal / message.Length * 1);
                    containerBox.Y = -(int)(messageLength / 1.6);

                    Font stringFont = new Font("verdana", messageLength);

                    StringFormat sf = new StringFormat();

                    float slope = (float)(Math.Atan2(newImage.Height, newImage.Width) * 180 / Math.PI);

                    gr.RotateTransform(slope);
                    gr.DrawString(message, stringFont, myBrush, containerBox, sf);
                    return newImage;
                }
            }
            catch (Exception exc)
            {
                throw exc;
            }
        }

        public int Calculations(decimal w1, decimal h1, int newWidth)
        {
            decimal height = 0;
            decimal ratio = 0;


            if (newWidth < w1)
            {
                ratio = w1 / newWidth;
                height = h1 / ratio;

                return height.To<int>();
            }

            if (w1 < newWidth)
            {
                ratio = newWidth / w1;
                height = h1 * ratio;
                return height.To<int>();
            }

            return height.To<int>();
        }

    }

Answer 6

Unless you resize up, you cannot do this with raster graphics.

What you can do with good filtering and smoothing is to resize without losing any noticable quality.

You can also alter the DPI metadata of the image (assuming it has some) which will keep exactly the same pixel count, but will alter how image editors think of it in 'real-world' measurements.

And just to cover all bases, if you really meant just the file size of the image and not the actual image dimensions, I suggest you look at a lossless encoding of the image data. My suggestion for this would be to resave the image as a .png file (I tend to use paint as a free transcoder for images in windows. Load image in paint, save as in the new format)