Memory allocated with alloca gets freed at end of

2019-06-16 06:28发布

If I have a function like this:

void bla(int size) {
    while(b){
        char tmp[size];
        ......
    }
}

tmp gets freed at each iteration of the while loop, right?

If I write this function:

void bla(int size) {
    while(b){
        char* tmp = alloca(size);
        ......
    }
}

tmp gets freed at end of scope or at end of function?

3条回答
狗以群分
2楼-- · 2019-06-16 07:09

alloca allocates on the stack and has no knowledge about scopes, so it gets freed after leaving the stack frame (= after leaving the function).

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Explosion°爆炸
3楼-- · 2019-06-16 07:24

Memory allocated with alloca() is deallocated when the function exits. See for instance the manual page for more information.

Regarding the former case, of just an auto-variable in the scope, I'm not sure how you would define that it gets "freed". You can't reference it outside of the scope that defines it, and if it had an initializer it would get re-initialized on each iteration.

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手持菜刀,她持情操
4楼-- · 2019-06-16 07:27

It will be freed at end of function, but since you call alloca() inside the loop you'll likely get stack overflow. If size doesn't change within the function you should call alloca() before the loop.

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