How do I send a cross-domain POST request via Java

Question

How do I send a cross-domain POST request via JavaScript?

Notes - it shouldn't refresh the page, and I need to grab and parse the response afterwards.

Answer 1

High level.... You need to have a cname setup on your server so that other-serve.your-server.com points to other-server.com.

Your page dynamically creates an invisible iframe, which acts as your transport to other-server.com. You then have to communicate via JS from your page to the other-server.com and have call backs that return the data back to your page.

Possible but requires coordination from your-server.com and other-server.com

Answer 2

Check the post_method function in http://taiyolab.com/mbtweet/scripts/twitterapi_call.js - a good example for the iframe method described above.

Answer 3

I know this is an old question, but I wanted to share my approach. I use cURL as a proxy, very easy and consistent. Create a php page called submit.php, and add the following code:

<?

function post($url, $data) {
$header = array("User-Agent: " . $_SERVER["HTTP_USER_AGENT"], "Content-Type: application/x-www-form-urlencoded");
$curl = curl_init();
curl_setopt($curl, CURLOPT_URL, $url);
curl_setopt($curl, CURLOPT_HTTPHEADER, $header);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($curl, CURLOPT_POST, 1);
curl_setopt($curl, CURLOPT_POSTFIELDS, $data);
$response = curl_exec($curl);
curl_close($curl);
return $response;
}

$url = "your cross domain request here";
$data = $_SERVER["QUERY_STRING"];
echo(post($url, $data));

Then, in your js (jQuery here):

$.ajax({
type: 'POST',
url: 'submit.php',
crossDomain: true,
data: '{"some":"json"}',
dataType: 'json',
success: function(responseData, textStatus, jqXHR) {
    var value = responseData.someKey;
},
error: function (responseData, textStatus, errorThrown) {
    alert('POST failed.');
}
});

Answer 4

Update: Before continuing everyone should read and understand the html5rocks tutorial on CORS. It is easy to understand and very clear.

If you control the server being POSTed, simply leverage the "Cross-Origin Resource Sharing standard" by setting response headers on the server. This answer is discussed in other answers in this thread, but not very clearly in my opinion.

In short here is how you accomplish the cross domain POST from from.com/1.html to to.com/postHere.php (using PHP as an example). Note: you only need to set Access-Control-Allow-Origin for NON OPTIONS requests - this example always sets all headers for a smaller code snippet.

1. In postHere.php setup the following:

   switch ($_SERVER['HTTP_ORIGIN']) {
       case 'http://from.com': case 'https://from.com':
       header('Access-Control-Allow-Origin: '.$_SERVER['HTTP_ORIGIN']);
       header('Access-Control-Allow-Methods: GET, PUT, POST, DELETE, OPTIONS');
       header('Access-Control-Max-Age: 1000');
       header('Access-Control-Allow-Headers: Content-Type, Authorization, X-Requested-With');
       break;
   }
   

   This allows your script to make cross domain POST, GET and OPTIONS. This will become clear as you continue to read...

2. Setup your cross domain POST from JS (jQuery example):

   $.ajax({
       type: 'POST',
       url: 'https://to.com/postHere.php',
       crossDomain: true,
       data: '{"some":"json"}',
       dataType: 'json',
       success: function(responseData, textStatus, jqXHR) {
           var value = responseData.someKey;
       },
       error: function (responseData, textStatus, errorThrown) {
           alert('POST failed.');
       }
   });
   

When you do the POST in step 2, your browser will send a "OPTIONS" method to the server. This is a "sniff" by the browser to see if the server is cool with you POSTing to it. The server responds with an "Access-Control-Allow-Origin" telling the browser its OK to POST|GET|ORIGIN if request originated from "http://from.com" or "https://from.com". Since the server is OK with it, the browser will make a 2nd request (this time a POST). It is good practice to have your client set the content type it is sending - so you'll need to allow that as well.

MDN has a great write-up about HTTP access control, that goes into detail of how the entire flow works. According to their docs, it should "work in browsers that support cross-site XMLHttpRequest". This is a bit misleading however, as I THINK only modern browsers allow cross domain POST. I have only verified this works with safari,chrome,FF 3.6.

Keep in mind the following if you do this:

1. Your server will have to handle 2 requests per operation
2. You will have to think about the security implications. Be careful before doing something like 'Access-Control-Allow-Origin: *'
3. This wont work on mobile browsers. In my experience they do not allow cross domain POST at all. I've tested android, iPad, iPhone
4. There is a pretty big bug in FF < 3.6 where if the server returns a non 400 response code AND there is a response body (validation errors for example), FF 3.6 wont get the response body. This is a huge pain in the ass, since you cant use good REST practices. See bug here (its filed under jQuery, but my guess is its a FF bug - seems to be fixed in FF4).
5. Always return the headers above, not just on OPTION requests. FF needs it in the response from the POST.

Answer 5

Should be possible with a YQL custom table + JS XHR, take a look at: http://developer.yahoo.com/yql/guide/index.html

I use it to do some client side (js) html scraping, works fine (I have a full audio player, with search on internet/playlists/lyrics/last fm informations, all client js + YQL)

Answer 6

One more important thing to note!!! In example above it's described how to use

$.ajax({
    type     : 'POST',
    dataType : 'json', 
    url      : 'another-remote-server',
    ...
});

JQuery 1.6 and lower has a bug with cross-domain XHR. According to Firebug no requests except OPTIONS were sent. No POST. At all.

Spent 5 hours testing/tuning my code. Adding a lot of headers on the remote server (script). Without any effect. But later, I've updated JQuery lib to 1.6.4, and everything works like a charm.