I am able to compare Strings fine, but would like to know how I can rank floating point numbers?
getChange() returns a String. I want to be able to sort descending. How can I do this?
UPDATE:
package org.stocktwits.helper;
import java.util.Comparator;
import org.stocktwits.model.Quote;
public class ChangeComparator implements Comparator<Quote>
{
public int compare(Quote o1, Quote o2) {
float change1 = Float.valueOf(o1.getChange());
float change2 = Float.valueOf(o2.getChange());
if (change1 < change2) return -1;
if (change1 == change2) return 0; // Fails on NaN however, not sure what you want
if (change2 > change2) return 1;
}
}
I am getting the compile time error:
This method must return a result of type int ChangeComparator.java
Read the javadoc of
Comparator#compare()
method.So, basically:
Or if you like conditional operators:
You however need to take account with
Float.NaN
. I am not sure how you'd like to have them ordered. First? Last? Equally?You can use
Float.compare(float f1, float f2)
:How about this:
Note that Java 1.4 introduced
Float#compare(float, float)
(and an equivalent inDouble
), which can be pretty much used directly:(After editing, I notice that @BorislavGizdov has mentioned this in his answer already.)
Also worth noting that Java 8
Comparator#comparing(...)
andComparator#comparingDouble(...)
provide a straightforward way of constructing these comparators directly.Will compare using boxed
Float
values.Will compare using
float
values promoted todouble
values.Given that there is no
Comparator#comparingFloat(...)
, my preference would be to use thecomparingDouble(...)
method, as this only involves primitive type conversion, rather than boxing.