How to extract the content of in a XML

Question

I have a document that it's structure is like below.
There are a lot of <entry>. My question is how can I output the <uri> of each entry? And another question, how can I output only the USERNAME?

This is the file I want to get the usernames http://search.twitter.com/search.atom?q=yankees

<?xml version="1.0" encoding="UTF-8"?>
<feed xmlns:google="http://base.google.com/ns/1.0" xml:lang="en-US" xmlns:openSearch="http://a9.com/-/spec/opensearch/1.1/" xmlns="http://www.w3.org/2005/Atom" xmlns:twitter="http://api.twitter.com/" xmlns:georss="http://www.georss.org/georss">

<entry>
  <author>
    <name></name>
      <uri>http://twitter.com/USERNAME</uri>
  </author>
</entry>

Answer 1

You should use SimpleXML some kind of a loop which goes trough all the s. (foreach($xml->entry as $entry) loop should work fine, I think.)

And for the second: if it is always http://twitter.com/USERNAME, simply count the prefix's length than use a substr.

Resources to use: substr, SimpleXML, SimpleXML

Answer 2

<?php
$xml = new DOMDocument;

// link to ur file
$xml->load('');    

foreach ($xml->getElementsByTagName('entry') as $product ) 
{
    $append = array();

    foreach($product->getElementsByTagName('uri') as $name ) {
        // Stick $name onto the array
        $append[] = $name;
    }
}

$result = $xml->saveXML();
print_r(str_replace('http://twitter.com/','',$result));
?>

Answer 3

You can use Xpath queries http://www.php.net/manual/en/simplexmlelement.xpath.php or http://php.net/manual/en/domxpath.query.php