Changing user agent on urllib2.urlopen

Question

How can I download a webpage with a user agent other than the default one on urllib2.urlopen?

Answer 1

Try this :

html_source_code = requests.get("http://www.example.com/",
                   headers={'User-Agent':'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/44.0.2403.107 Safari/537.36',
                            'Upgrade-Insecure-Requests': '1',
                            'x-runtime': '148ms'}, 
                   allow_redirects=True).content

Answer 2

headers = { 'User-Agent' : 'Mozilla/5.0' }
req = urllib2.Request('www.example.com', None, headers)
html = urllib2.urlopen(req).read()

Or, a bit shorter:

req = urllib2.Request('www.example.com', headers={ 'User-Agent': 'Mozilla/5.0' })
html = urllib2.urlopen(req).read()

Answer 3

All these should work in theory, but (with Python 2.7.2 on Windows at least) any time you send a custom User-agent header, urllib2 doesn't send that header. If you don't try to send a User-agent header, it sends the default Python / urllib2

None of these methods seem to work for adding User-agent but they work for other headers:

opener = urllib2.build_opener(proxy)
opener.addheaders = {'User-agent':'Custom user agent'}
urllib2.install_opener(opener)

request = urllib2.Request(url, headers={'User-agent':'Custom user agent'})

request.headers['User-agent'] = 'Custom user agent'

request.add_header('User-agent', 'Custom user agent')

Answer 4

there are two properties of urllib.URLopener() namely:
addheaders = [('User-Agent', 'Python-urllib/1.17'), ('Accept', '*/*')] and
version = 'Python-urllib/1.17'.
To fool the website you need to changes both of these values to an accepted User-Agent. for e.g.
Chrome browser : 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/33.0.1750.149 Safari/537.36'
Google bot : 'Googlebot/2.1'
like this

import urllib
page_extractor=urllib.URLopener()  
page_extractor.addheaders = [('User-Agent', 'Googlebot/2.1'), ('Accept', '*/*')]  
page_extractor.version = 'Googlebot/2.1'
page_extractor.retrieve(<url>, <file_path>)

changing just one property does not work because the website marks it as a suspicious request.

Answer 5

I answered a similar question a couple weeks ago.

There is example code in that question, but basically you can do something like this: (Note the capitalization of User-Agent as of RFC 2616, section 14.43.)

opener = urllib2.build_opener()
opener.addheaders = [('User-Agent', 'Mozilla/5.0')]
response = opener.open('http://www.stackoverflow.com')

Answer 6

For python 3, urllib is split into 3 modules...

import urllib.request
req = urllib.request.Request(url="http://localhost/",data=b'None',headers={'User-Agent':' Mozilla/5.0 (Windows NT 6.1; WOW64; rv:12.0) Gecko/20100101 Firefox/12.0'})
handler = urllib.request.urlopen(req)