How to remove unused C/C++ symbols with GCC and ld

2018-12-31 15:44发布

I need to optimize the size of my executable severely (ARM development) and I noticed that in my current build scheme (gcc + ld) unused symbols are not getting stripped.

The usage of the arm-strip --strip-unneeded for the resulting executables / libraries doesn't change the output size of the executable (I have no idea why, maybe it simply can't).

What would be the way (if it exists) to modify my building pipeline, so that the unused symbols are stripped from the resulting file?


I wouldn't even think of this, but my current embedded environment isn't very "powerful" and saving even 500K out of 2M results in a very nice loading performance boost.

Update:

Unfortunately the current gcc version I use doesn't have the -dead-strip option and the -ffunction-sections... + --gc-sections for ld doesn't give any significant difference for the resulting output.

I'm shocked that this even became a problem, because I was sure that gcc + ld should automatically strip unused symbols (why do they even have to keep them?).

标签: c++ c gcc ld strip
11条回答
有味是清欢
2楼-- · 2018-12-31 15:55

While not strictly about symbols, if going for size - always compile with -Os and -s flags. -Os optimizes the resulting code for minimum executable size and -s removes the symbol table and relocation information from the executable.

Sometimes - if small size is desired - playing around with different optimization flags may - or may not - have significance. For example toggling -ffast-math and/or -fomit-frame-pointer may at times save you even dozens of bytes.

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孤独寂梦人
3楼-- · 2018-12-31 15:56

If this thread is to be believed, you need to supply the -ffunction-sections and -fdata-sections to gcc, which will put each function and data object in its own section. Then you give and --gc-sections to GNU ld to remove the unused sections.

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若你有天会懂
4楼-- · 2018-12-31 15:56

strip --strip-unneeded only operates on the symbol table of your executable. It doesn't actually remove any executable code.

The standard libraries achieve the result you're after by splitting all of their functions into seperate object files, which are combined using ar. If you then link the resultant archive as a library (ie. give the option -l your_library to ld) then ld will only include the object files, and therefore the symbols, that are actually used.

You may also find some of the responses to this similar question of use.

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唯独是你
5楼-- · 2018-12-31 15:57

The answer is -flto. You have to pass it to both your compilation and link steps, otherwise it doesn't do anything.

It actually works very well - reduced the size of a microcontroller program I wrote to less than 50% of its previous size!

Unfortunately it did seem a bit buggy - I had instances of things not being built correctly. It may have been due to the build system I'm using (QBS; it's very new), but in any case I'd recommend you only enable it for your final build if possible, and test that build thoroughly.

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其实,你不懂
6楼-- · 2018-12-31 15:57

You can use strip binary on object file(eg. executable) to strip all symbols from it.

Note: it changes file itself and don't create copy.

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与君花间醉酒
7楼-- · 2018-12-31 16:01

I don't know if this will help with your current predicament as this is a recent feature, but you can specify the visibility of symbols in a global manner. Passing -fvisibility=hidden -fvisibility-inlines-hidden at compilation can help the linker to later get rid of unneeded symbols. If you're producing an executable (as opposed to a shared library) there's nothing more to do.

More information (and a fine-grained approach for e.g. libraries) is available on the GCC wiki.

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